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statuscvo [17]
3 years ago
6

The sum of two numbers is 119. If 4 times the smaller number is subtracted from the larger number the result is nine. Find a two

numbers.
Mathematics
1 answer:
astraxan [27]3 years ago
8 0

The larger number is 97 and smaller number is 22.

Step-by-step explanation:

Let,

The two numbers are x and y.

According to given statement;

x+y=119      Eqn 1

y-4x=9       Eqn 2

Subtracting Eqn 2 from Eqn 1

(x+y)-(y-4x)=119-9\\x+y-y+4x=110\\5x=110

Dividing both sides by 5

\frac{5x}{5}=\frac{110}{5}\\x=22

Putting x=22 in Eqn 1

22+y=119\\y=119-22\\y=97

The larger number is 97 and smaller number is 22.

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/10196212
  • brainly.com/question/1021953

#LearnwithBrainly

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Find the volume of a right circular cone that has a height of 20 ft and a base with a
maksim [4K]
Your answer will be 1733.489333ft³
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1733.1ft³
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7 0
3 years ago
Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be
hodyreva [135]

Answer:

\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305

s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108

\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105

s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221

The absolute difference is:

Abs = |340.221-115.108|= 225.113

If we find the % of change respect the before case we have this:

\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305

And the sample deviation with the following formula:

s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105

And the sample deviation with the following formula:

s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

Abs = |340.221-115.108|= 225.113

If we find the % of change respect the before case we have this:

\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%

So then is a big change.

8 0
3 years ago
Muffins are packed and sold in boxes of 4. How many boxes are needed to pack 260 muffins?
Volgvan

Answer:

65 boxes

Step-by-step explanation:

Im not sure how to explain other then say all you do is divide 260 and 4

I hope this helped!

Good luck!

If i did help maybe you could help me by giving me brainliest!?

Thanks! <3

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nirvana33 [79]
As you are looking for 1.75 minutes (or 105 seconds), the best thing to do is to find how many words she can type in 0.25 minutes (this is a quarter, and you can divide 1.75 by this). To find a quarter, you have to divide by 4, 120/4= 30. Therefore, every 15 seconds, Dorothy can type 30 words. As you've got 105 seconds, divide this by 15, and this gives you 7. Then multiply 30 by 7, and this gives you 210.
Dorothy can type 210 words in 1.75 minutes
Hope this helps :)  
8 0
3 years ago
Read 2 more answers
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Allushta [10]

Answer:

0

Step-by-step explanation:

-10 to -6 is 4 paces so you do 4 more paces and then half of that percent and you get 0.

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