F(x) is continuous for all x.
Pick a point and show that f(x) is either negative or positive. Pick another point and show that f(x) is negative, if positive, or positive, if negative.
At x = 30, f(30) - 1000 = 900 + 10sin(30) - 1000 ≤ 0
Now, show at another point f(x) - 1000 is positive, and hence, there would be root between 30 and such point.
Let's pick 40.
At x = 40, f(40) - 1000 = 1600 + 10sin(40) - 1000 ≥ 0
Since f(x) - 1000 is continuous, there lies a root between 30 and 40, and hence, 30 ≤ c ≤ 40
Answer:
x = 5
Step-by-step explanation:
x + 5 = 
{Midpoint theorem}
2(x+ 5) = x² - x
2x + 10 = x² - x
x² - x - 2x - 10 = 0
x² - 3x - 10 = 0
x² - 5x + 2x - (5*2) = 0
x(x - 5) + 2(x - 5) = 0
(x -5)(x + 2) = 0
{x + 2 is ignored because measurement could not be in negative value}
x - 5 = 0
x = 5
5n-4 = 6 gives the equation for 5 times #Nathan rode less 4 miles which solves to n = 2
Nathan rode 2 miles. (5*2)-4 = 6 10-4=6 so 2 miles is right
