The solution to given system of equations is (x, y) = (2, -1)
<em><u>Solution:</u></em>
Given system of equations are:
-1x + 2y = -4 -------- eqn 1
4x + 3y = 5 ------- eqn 2
We can solve the above system of equations by elimination method
<em><u>Multiply eqn 1 by 4</u></em>
4(-1x + 2y = -4)
-4x + 8y = -16 ------ eqn 3
<em><u>Add eqn 2 and eqn 3</u></em>
4x + 3y = 5
-4x + 8y = -16
( + ) --------------------
0x + 11y = -16 + 5
11y = -11
y = -1
<em><u>Substitute y = -1 in eqn 1</u></em>
-1x + 2(-1) = -4
-x -2 = -4
-x = -4 + 2
-x = -2
x = 2
<em><u>Check the answer:</u></em>
Substitute x = 2 and y = -1 in eqn 2
4x + 3y = 5
4(2) + 3(-1) = 5
8 - 3 = 5
5 = 5
Thus the obtained answer is correct
Thus the solution to given system of equations is (x, y) = (2, -1)
All you have to do is substitute the values in for y to see if they are true.
0: 9 ≤ 6 - 0 = 9 ≤ 6 (FALSE)
3: 9 ≤ 6 - 3 = 9 ≤ 3 (FALSE)
-3: 9 ≤ 6 - -3 = 9 ≤ 9 (TRUE)
-1: 9 ≤ 6 - -1 = 9 ≤ 7 (FALSE)
-6: 9 ≤ 6 - -6 = 9 ≤ 12 (TRUE)
6: 9 ≤ 6 - 6 = 9 ≤ 0 (FALSE)
-4: 9 ≤ 6 - -4 = 9 ≤ 10 (TRUE)
So, the values that belong to 9 ≤ 6 - y are -3, -4, and -6.
Answer:
the period of this graph is 2
Step-by-step explanation:
The period is the length of the section that repeats. So for this graph, we need to calculate the distance between 2 peaks or 2 troughs of the curve.
Let's look at the peaks (maximums).
One is at x = 0 and the next is at x = 2
2 - 0 = 2
Therefore, the period of this graph is 2
48
1st seat 6 possible for each 6 only 1 possible(spouse) for seat 2
3rd seat 4 possible for each 4 only 1 possible(spouse) for seat 4
5th seat 2 possible for each 2 only 1 possible(spouse) for seat 6
6 x 4 x 2 = 48
OR 3 couples possible arrangements 3 x 2 x1 = 6
each couple 2 possible 2 x 2 x 2 = 8
therefore 6 x 8 = 48
