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3 years ago

Mrs.davis wants to feed the guinea pigs 3/4 of a 12 ounce bag of pet food. How many ounces does she need ?

Mathematics

2 answers:

Hunter-Best [27]3 years ago

6 0

Answer:

she wants 9

Step-by-step explanation:

motikmotik3 years ago

6 0

Answer:

Fresh vegetables can be offered once a day and should be equivalent to about one cup total per guinea pig per dayLeafy greens like romaine lettuce, spinach, kale or parsley should comprise the bulk of your pig's fresh produce.

Step-by-step explanation:

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How do you plot a linear graph

dlinn [17]

Step-by-step explanation:

You can plot linear graph using two point (x1,y1) and (x2,y2), where x1, y1, x2 and y2 are real numbers.

using slope intercept form y = mx + b, where m is the slope and b is y-intercept.

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4 years ago

Can I have help please I am stuck on this question it would mean the world if u helped me have a nice day! =) <3

guajiro [1.7K]

Answer:

Step-by-step explanation:

1m = 100cm

0.8m = 100*0.8 = 80cm

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3 years ago

Let X1 and X2 be independent random variables with mean μand variance σ².

My name is Ann [436]

Answer:

a) $E(\hat \theta_1) =\frac{1}{2} [E(X_1) +E(X_2)]= \frac{1}{2} [\mu + \mu] = \mu$

So then we conclude that $\hat \theta_1$ is an unbiased estimator of $\mu$

$E(\hat \theta_2) =\frac{1}{4} [E(X_1) +3E(X_2)]= \frac{1}{4} [\mu + 3\mu] = \mu$

So then we conclude that $\hat \theta_2$ is an unbiased estimator of $\mu$

b) $Var(\hat \theta_1) =\frac{1}{4} [\sigma^2 + \sigma^2 ] =\frac{\sigma^2}{2}$

$Var(\hat \theta_2) =\frac{1}{16} [\sigma^2 + 9\sigma^2 ] =\frac{5\sigma^2}{8}$

Step-by-step explanation:

For this case we know that we have two random variables:

$X_1 , X_2$ both with mean $\mu = \mu$ and variance $\sigma^2$

And we define the following estimators:

$\hat \theta_1 = \frac{X_1 + X_2}{2}$

$\hat \theta_2 = \frac{X_1 + 3X_2}{4}$

Part a

In order to see if both estimators are unbiased we need to proof if the expected value of the estimators are equal to the real value of the parameter:

$E(\hat \theta_i) = \mu , i = 1,2$

So let's find the expected values for each estimator:

$E(\hat \theta_1) = E(\frac{X_1 +X_2}{2})$

Using properties of expected value we have this:

$E(\hat \theta_1) =\frac{1}{2} [E(X_1) +E(X_2)]= \frac{1}{2} [\mu + \mu] = \mu$

So then we conclude that $\hat \theta_1$ is an unbiased estimator of $\mu$

For the second estimator we have:

$E(\hat \theta_2) = E(\frac{X_1 + 3X_2}{4})$

Using properties of expected value we have this:

$E(\hat \theta_2) =\frac{1}{4} [E(X_1) +3E(X_2)]= \frac{1}{4} [\mu + 3\mu] = \mu$

So then we conclude that $\hat \theta_2$ is an unbiased estimator of $\mu$

Part b

For the variance we need to remember this property: If a is a constant and X a random variable then:

$Var(aX) = a^2 Var(X)$

For the first estimator we have:

$Var(\hat \theta_1) = Var(\frac{X_1 +X_2}{2})$

$Var(\hat \theta_1) =\frac{1}{4} Var(X_1 +X_2)=\frac{1}{4} [Var(X_1) + Var(X_2) + 2 Cov (X_1 , X_2)]$

Since both random variables are independent we know that $Cov(X_1, X_2 ) = 0$ so then we have:

$Var(\hat \theta_1) =\frac{1}{4} [\sigma^2 + \sigma^2 ] =\frac{\sigma^2}{2}$

For the second estimator we have:

$Var(\hat \theta_2) = Var(\frac{X_1 +3X_2}{4})$

$Var(\hat \theta_2) =\frac{1}{16} Var(X_1 +3X_2)=\frac{1}{4} [Var(X_1) + Var(3X_2) + 2 Cov (X_1 , 3X_2)]$

Since both random variables are independent we know that $Cov(X_1, X_2 ) = 0$ so then we have:

$Var(\hat \theta_2) =\frac{1}{16} [\sigma^2 + 9\sigma^2 ] =\frac{5\sigma^2}{8}$

7 0

3 years ago

Find the quotient of quantity of 4 times x to the 3rd power minus 12 times x to the 2nd power plus 8 times x all over negative 4

Readme [11.4K]

$\displaystyle \frac{4x^3-12x^2+8x}{-4x}=\frac{4x^3}{-4x}+\frac{-12x^2}{-4x}+\frac{8x}{-4x}\\\\=-x^2+3x-2$

This result corresponds to the first selection.

5 0

4 years ago

Suppose that J and K are points on the number line. If JK=12 lies at 3 , where could K be located? If there are several location

zmey [24]

Answer:

15, -9

Step-by-step explanation:

It is given that J and K are points on the number line. J lies at 3 and JK=12.

We kneed to find the location of K.

A number line is a straight line with numbers placed at equal intervals and extended infinitely in any direction.

If K lies on the left side of J then the location of K is

3 + 12 = 15

If K lies on the right side of J then the location of K is

3 - 12 = -9

The locations of K are defined by the below number.

Therefore the locations of K are 15 and -9.

8 0

3 years ago