Worth 20 points!! Tell me an x, y ordered pair that is a solution for this equation. Y = 5x - 2
1 answer:
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Answer:
See Explanation
Step-by-step explanation:
The number lines to make selection from are missing from the question.
<em>However, I've attached 4 number lines, each of which represents each of the given irrational numbers (see attachment)</em>
<em></em>
<u>Number: 2.1823912</u>
This is represented by number line 1
Each point of number line 3 is 0.001 units starting from 2.18;
The point which the red dot is located is between 2.182 and 2.183, but the dot is closer to 2.182.
<em>2.1823912 and 2.1829391321 satisfy this property but number line 2 represents 2.1829391321 (see below for explanation)</em>
So: 2.1823912 is represented by number line 1
<u></u>
<u>Number: 2.1829391321</u>
This is represented by number line 2.
Each point of number line 3 is 0.0001 units starting from 2.182;
The point which the red dot is located is between 2.1829 and 2.1830, but the dot is closer to 2.1829.
From the list of given numbers, only 2.1829391321 satisfy this property.
<em />
<u>Number: 2.18112...</u>
This is represented by number line 3.
Each point of number line 3 is 0.01 units starting from 2.11;
The point which the red dot is located is between 2.18 and 2.19.
If number lines 1 and 2 represent 2.1823912 and 2.1829391321, respectively, then number line 3 represents 2.18112.
<u></u>
<u>Number: 2.364125 </u>
This is represented by number line 4.
Each point on this number line is 0.1 unit starting from 2.0;
The point which the red dot is located is between 2.30 and 2.40. From the list of given numbers, only 2.364125 satisfy this property.
Answer:
- AH = 3.2
- CH = 1.8
- BH = 2.4
Step-by-step explanation:
It can be convenient to compute the length of the hypotenuse of this triangle (AC). The Pythagorean theorem tells you ...
AC^2 = AB^2 + CB^2
AC^2 = 4^2 + 3^2 = 16 + 9 = 25
AC = √25 = 5
The altitude divides ∆ABC into similar triangles ∆AHB and ∆BHC. The scale factor for ∆AHB is ...
scale factor ∆ABC to ∆AHB = AB/AC = 4/5 = 0.8
And the scale factor to ∆BHC is ...
scale factor ∆ABC to ∆BHC = BC/AC = 3/5 = 0.6
Then the side AH is 0.8·AB = 0.8·4 = 3.2
And the side CH is 0.6·BC = 0.6·3 = 1.8
These two side lengths should add to the length AC = 5, and they do.
The remaining side BH can be found from either scale factor:
BH = AB·0.6 = BC·0.8 = 4·0.6 = 3·0.8 = 2.4
_____
The sides of interest are ...
AH = 3.2
CH = 1.8
BH = 2.4
