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GaryK [48]
3 years ago
7

Someone help please i dont know how to do this

Mathematics
1 answer:
Olenka [21]3 years ago
3 0

Area of the parallelogram = 14 * PQ

Area of the triangle

= 1/2 * PQ*MQ = 1/6 * 14 * PQ

Divide through by PQ

1/2 MQ = 1/6 * 14

MQ = 1/6 * 14 * 2 = 4 2/3 cm^3 ( or 4.67 cm^3 to nearest hundredth.)

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How many solutions does the equation sin(5x) = 1/2 have on the interval (0, 2PI]
Darina [25.2K]

Answer:

Step-by-step explanation:

Given the equation

Sin(5x) = ½

5x = arcSin(½)

5x = 30°

Then,

The general formula for sin is

5θ = n180 + (-1)ⁿθ

Divide through by 5

θ = n•36 + (-1)ⁿ30/5

θ = 36n + (-1)ⁿ6

The range of the solution is

0<θ<2π I.e 0<θ<360

First solution

When n = 0

θ = 36n + (-1)ⁿθ

θ = 0×36 + (-1)^0×6

θ = 6°

When n = 1

θ = 36n + (-1)ⁿ6

θ = 36-6

θ = 30°

When n = 2

θ = 36n + (-1)ⁿ6

θ = 36×2 + 6

θ = 78°

When n =3

θ = 36n + (-1)ⁿ6

θ = 36×3 - 6

θ = 102°

When n=4

θ = 36n + (-1)ⁿ6

θ = 36×4 + 6

θ = 150

When n =5

θ = 36n + (-1)ⁿ6

θ = 36×5 - 6

θ = 174°

When n = 6

θ = 36n+ (-1)ⁿ6

θ = 36×6 + 6

θ = 222°

When n = 7

θ = 36n + (-1)ⁿ6

θ = 36×7 - 6

θ = 246°

When n =8

θ = 36n + (-1)ⁿ6

θ = 36×8 + 6

θ = 294°

When n =9

θ = 36n + (-1)ⁿ6

θ = 36×9 - 6

θ = 318°

When n =10

θ = 36n + (-1)ⁿ6

θ = 36×10 + 6

θ = 366°

When n = 10 is out of range of θ

Then, the solution is from n =0 to n=9

So the equation have 10 solutions in the range 0<θ<2π

4 0
3 years ago
Hurry please, 20 points
nekit [7.7K]

Answer:

Step-by-step explanation:

Parallel slope = -8

Perpendicular slope = 1/8

5 0
3 years ago
Read 2 more answers
What is the value of x? 
Marrrta [24]
I dont know i just want coins lol
plus i just dont know

3 0
3 years ago
Last question needed for mastery please help thank you!
liraira [26]
A= P(1+r)^t, where P= initial value, r= interest rate in %, and t = number of years.
However, if there isa decrease in value, the formula becomes:

A= P(1-r)^t and in our case :

A = 30,000(1- 0.24)^t  OR A = 30,000(0.76)^t



5 0
3 years ago
Which transformation was applied to figure A to form figure B?
PtichkaEL [24]

Answer:

B

Step-by-step explanation:

Let point N has coordinates (0,0), then figure A has vertices at points (-3,0), (-7,0), (-7,4) and (-3,4). Figure B has vertices at points (3,1), (7,1), (7,-3) and (3,-3).

1. Translation 10 units to the right has the rule

(x,y)→(x+10,y).

Then vertices of the figure A have images:

  • (-3,0)→(7,0);
  • (-7,0)→(3,0);
  • (-7,4)→(3,4);
  • (-3,4)→(7,4).

2. Translation 3 units down has the rule

(x,y)→(x,y-3).

Then images are

  • (7,0)→(7,-3);
  • (3,0)→(3,-3);
  • (3,4)→(3,1);
  • (7,4)→(7,1).

As you can see these points are exactly the vertices of the figure B.

4 0
3 years ago
Read 2 more answers
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