What is the value of x?
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I assume you meant "surface area" :)
Looking at the net, it looks like if you folded it back together it would form to become a triangular prism.
To calculate the surface area of a triangular prism, you would use the formula: A = bh + 2ls + lb, where b is the base of the triangular faces, h is the height of the prism, l is the length of the prism, and s is the side length of the prism.
I attached a picture to help you see what these labels are.
Looking at the diagram you've provided, we can assume that b = 7 cm, h = 4 cm, l = 8 cm, and s = 5 cm. Substitute these into the formula.
A = bh + 2ls + lb ==> A = (7)(4) + 2(8)(5) + (8)(7)
Multiply from left to right.
28 + 80 + 56
Add.
164
The surface area of this triangular prism is A) 164 cm^2.
At first we need to know how to find the distance between two parallel lines
The parallel lines which have the same slope
If we have two parallel lines ⇒ y₁ = mx + c₁ and y₂ = mx + c₂
So, the distance between y₁ and y₂ = d =
========================================================
Part (1):
=======
<span>The distance between the lines
</span>
<span> Y₁ = 3x + 10 and Y₂ = 3x - 20</span>
∴ m = 3 , c₁ = 10 and c₂ = -20
∴ d =
========================================================
Part (2):
=======
<span>The distance between the lines
</span>
Y₁ = <span>3/2 x + 3/2</span> and Y₂ = <span>3/2 x - 5</span>
∴ m = 3/2 = 1.5 , c₁ = 3/2 = 1.5 and c₂ = -5
∴ d =
The parallel lines which have the same slope
If we have two parallel lines ⇒ y₁ = mx + c₁ and y₂ = mx + c₂
So, the distance between y₁ and y₂ = d =
========================================================
Part (1):
=======
<span>The distance between the lines
</span>
<span> Y₁ = 3x + 10 and Y₂ = 3x - 20</span>
∴ m = 3 , c₁ = 10 and c₂ = -20
∴ d =
========================================================
Part (2):
=======
<span>The distance between the lines
</span>
Y₁ = <span>3/2 x + 3/2</span> and Y₂ = <span>3/2 x - 5</span>
∴ m = 3/2 = 1.5 , c₁ = 3/2 = 1.5 and c₂ = -5
∴ d =