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ehidna [41]
4 years ago
7

Please help. Brainilist + 50

Mathematics
2 answers:
Trava [24]4 years ago
8 0
X is equal is 3 over 2. If you find the slope, the slope is 3 over 2.
Simply, it is
anzhelika [568]4 years ago
5 0
The slope is 3 over 2. for your answer

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What percent is 608 million of 845 million? Round to the nearest 100th place and Enter your answer with the percent symbol.
bezimeni [28]

Answer: 72%

Step-by-step explanation: Well, we want to know what percent 608 is of 845, so to solve that, let's call 845 100%, as we're solving it terms of 845. 845 is 100%, then it follows that 8.45 is 1%.

Now we can see how many 8.45's go into 608, which comes out to 71.95266...%, which can be rounded nicely to 72%

8 0
3 years ago
Q# ..7 match the equation with its graph -4x - 2y =8
prisoha [69]

If you divide by 8, you can put the equation into intercept form. That form is ...

... x/a + y/b = 1

where <em>a</em> and <em>b</em> are the x- and y-intercepts, respectively.

Here, your equation would be

... x/(-2) + y/(-4) = 0

The graph with those intercepts is not shown with your problem statement here. See the attachment for the graph.

3 0
4 years ago
4x-2y=-2<br> 3x+2y=-12<br><br> Solve by using elimination
andreyandreev [35.5K]
Point form: (-2,-3)
Equation form: x=-2, y=-3
7 0
4 years ago
The graph of y= -5x + 1 is:
notsponge [240]

Answer: Slope: −5

y-intercept: (0,1)

x= 0 , 1

y= 1 , −4

7 0
3 years ago
How would you solve this problem?
klio [65]

Answer:

a) 6x²/2x³-4

b)  2ln (2x^3-4)+ C

Step-by-step explanation:

a) Given the ln(2x³-4). We will use the chain rule in differentiating the function

If y = ln(2x³-4);

u = 2x³-4; du/dx = 3(2)x³⁻¹

du/dx = 6x²

y = ln u; dy/du = 1/u

According to chain rule, dy/dx = dy/dy*du/dx

dy/dx = 1/u * 6x²

dy/dx = 1/2x³-4 * 6x²

dy/dx = 6x²/2x³-4

Hence, the derivative of the given function is 6x²/2x³-4

b) Given an integral function \int\limits {\frac{12x^2}{2x^3-4} } \, dx, the integral problem can be solved using integration by substitution method as shown below;

From the question, let y = 2x³-4... 1, dy/dx = 6x²

dx = dy/6x² ... 2

Substituting equation 1 and 2 into the question given;

\int\limits {\frac{12x^2}{y} } \,\frac{dy}{6x^2} \\\\= \int\limits {\frac{2dy}{y} } \\\\= 2 \int\limits {\frac{dy}{y} }\\\\= 2lny + C\\substituting\ y = 2x^3-4\ into\ the \ resulting\ function\\\\= 2ln (2x^3-4)+ C

3 0
4 years ago
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