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sdas [7]
3 years ago
11

A courier worked 39 hours and earned $429, which included some compensation for paid time off. If his true hourly wage is $3 per

hour more than the pay rate shown on his pay stub, what rate is shown on his pay stub?
Hint: The true hourly wage is the earnings on the pay stub divided by the hours worked.

A. $17 per hour
B. $8 per hour
C. $13 per hour
D. $11 per hour
Mathematics
2 answers:
marishachu [46]3 years ago
7 0
Answer: (B) $8.00 per hour



Hope this helps.
dmitriy555 [2]3 years ago
7 0

Answer:

Option B is correct.

Step-by-step explanation:

Number of hours A courier worked = 39

Money a courier earned  = $ 429

⇒ Hourly Wage of the courier = \frac{429}{39}

                                                  = $ 11 per hour

Let x be the rate shown on his pay stub.

According tot he Question,

x + 3 = 11

x = 11 - 3

x = 8

Therefor, Option B is correct.

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Find the product of (2x-3) and (x+3)​
miss Akunina [59]

Answer:

(2x - 3) * (x + 3)

=> (2x * x) + (-3 * 3)

=> 2x - 9

=> 2x -9

If my answer helped, kindly mark me as the brainliest!!

Thank You!!

3 0
2 years ago
A certain disease has an incidence rate of 0.1%. If the false negative rate is 8%
defon

Answer: 0.31 or 31%

Let A be the event that the disease is present in a particular person

Let B be the event that a person tests positive for the disease

The problem asks to find P(A|B), where

P(A|B) = P(B|A)*P(A) / P(B) = (P(B|A)*P(A)) / (P(B|A)*P(A) + P(B|~A)*P(~A))

In other words, the problem asks for the probability that a positive test result will be a true positive.  

P(B|A) = 1-0.02 = 0.98 (person tests positive given that they have the disease)

P(A) = 0.009 (probability the disease is present in any particular person)

P(B|~A) = 0.02 (probability a person tests positive given they do not have the disease)

P(~A) = 1-0.009 = 0.991 (probability a particular person does not have the disease)

P(A|B) = (0.98*0.009) / (0.98*0.009 + 0.02*0.991)

= 0.00882 / 0.02864 = 0.30796

*round however you need to but i am leaving it at 0.31 or 31%*

If you found this helpful please mark brainliest

3 0
2 years ago
How can the bar symbol be used to show the quotient of 7÷11 if the division is carried on forever?
Thepotemich [5.8K]

\bf 7\div 11\implies 0.636363636363636........\implies 0.\overline{63}

4 0
3 years ago
PLEASE HELP ME PLEASE HELP
aliina [53]
To grandparents house :
140/56 = 2.5 hours

Return trip :
140/50 = 2.8 hours

Total time : 2.8+2.5 = 5.3 hours
7 0
3 years ago
Read 2 more answers
I don't get it and I have tried it multiple ways
jasenka [17]

9514 1404 393

Answer:

  9350 m²

Step-by-step explanation:

There are several ways you can go at this. Here are 3 of them:

  1. along an extension of the lower right vertical edge, divide the figure into a rectangle and a right triangle.
  2. between the upper left corner and the inside corner at lower right draw a diagonal line to divide the figure into a trapezoid and a triangle.
  3. subtract the area of the trapezoid at the right from the area of the bounding rectangle

__

The relevant formulas for area are ...

  rectangle: A = LW . . . . . . . . . . . length times width

  trapezoid: A = (1/2)(b1 +b2)h . . . b1, b2 are the bases, h is the height

  triangle: A = (1/2)bh . . . . . . . . . . . b is the base, h is the height

__

Here's what those computations look like:

1. rectangle: 60m wide by 80 m high = 4800 m².

  right triangle: base 190-60 = 130 m; height = 80-10 = 70 m.

     area = (1/2)(130 m)(70 m) = 4550 m²

  figure area = 4800 m² +4550 m² = 9350 m² . . . . area of figure

__

2. The trapezoid has bases of 80 m and 10 m, and a height of 60 m. Its area is ...

  A = (1/2)(80 m +10 m)(60 m) = 2700 m²

The triangle has a base of 190 m and a height of 80-10 = 70 m. Its area is ...

  A = (1/2)(190 m)(70 m) = 6650 m²

Then the total area is 2700 m² +6650 m² = 9350 m² . . . total area

__

3. The bounding rectangle is 190 m by 80 m, so its area is ...

  A = LW = (190 m)(80 m) = 15200 m²

The (negative) trapezoid at right has bases of 10 m and 80 m, and a width of 190-60 = 130 m. Its area is ...

  A = (1/2)(10 m +80 m)(130 m) = 5850 m²

The area of the figure is the difference between these:

  figure area = 15200 m² -5850 m² = 9350 m² . . . figure area

7 0
3 years ago
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