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3 years ago

The Bilbo Company plans to manufacture decals for children's lunchboxes. Each decal

Mathematics

1 answer:

Gwar [14]3 years ago

4 0

Answer: 1 -2ax²+2x-ax

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Area of a rectangle: length x width

Replacing with the values given:

A = (2x+1) (1-ax)

A = [2x(1)] + [2x(-ax)] +[ 1(1)]+ [1 (-ax)]

A = 2x- 2ax² +1- ax

A = 1 -2ax²+2x-ax

In conclusion, the correct option is 1 -2ax²+2x-ax

Feel free to ask for more if needed or if you did not understand something.

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Use the triangle below to find cos V.

Semenov [28]

Answer:

$cos\ V = \frac{2\sqrt{29}}{29}$

Step-by-step explanation:

Given

The attached triangle

Required

Find cos V

In trigonometry:

$cos\theta = \frac{Adjacent}{Hypotenuse}$

In this case:

$cos V= \frac{TV}{UV}$

Where

$TV = 6$

and

$UV^2 = TV^2 + TU^2$ -- Pythagoras

$UV^2 = 6^2 + 15^2$

$UV^2 = 261$

Take square roots

$UV = \sqrt{261$

$UV = \sqrt{9*29$

$UV = \sqrt{9} *\sqrt{29$

$UV = 3\sqrt{29$

So:

$cos V= \frac{TV}{UV}$

$cos\ V = \frac{6}{3\sqrt{29}}$

$cos\ V = \frac{2}{\sqrt{29}}$

Rationalize:

$cos\ V = \frac{2}{\sqrt{29}}*\frac{\sqrt{29}}{\sqrt{29}}$

$cos\ V = \frac{2\sqrt{29}}{29}$

8 0

2 years ago

Part A: Victor is studying for his Finais. He spends 1/3 of an hour studying for History, 2/3 an hour

Elan Coil [88]

Answer:

3 3/4

Step-by-step explanation: all that you have to do is add 1/3 +2/3+11/4 which gives you 3 3/4

4 0

2 years ago

Enter a positive common favor (other than 1) of the fractions numerator and denominator

Romashka [77]

Answer:

Step-by-step explanation:

You can divide both 14 and 21 by seven and get a whole number.

6 0

3 years ago

Read 2 more answers

What is 576 divided into 4

vesna_86 [32]

Answer:

144

Step-by-step explanation:

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3 years ago

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A set of ordered pairs is called ordered pairs is called

Amiraneli [1.4K]

A set of ordered pairs is called a relation. The set of all first components of the ordered pairs of a relation is the domain of the relation, and the set of all second components of the ordered pairs is the range of the relation. :)

4 0

3 years ago