First, "boxes of two sizes" means we can assign variables: Let x = number of large boxes y = number of small boxes "There are 115 boxes in all" means x + y = 115 [eq1] Now, the pounds for each kind of box is: (pounds per box)*(number of boxes) So, pounds for large boxes + pounds for small boxes = 4125 pounds "the truck is carrying a total of 4125 pounds in boxes" (50)*(x) + (25)*(y) = 4125 [eq2] It is important to find two equations so we can solve for two variables. Solve for one of the variables in eq1 then replace (substitute) the expression for that variable in eq2. Let's solve for x: x = 115 - y [from eq1] 50(115-y) + 25y = 4125 [from eq2] 5750 - 50y + 25y = 4125 [distribute] 5750 - 25y = 4125 -25y = -1625 y = 65 [divide both sides by (-25)] There are 65 small boxes. Put that value into either equation (now, which is easier?) to solve for x: x = 115 - y x = 115 - 65 x = 50 There are 50 large boxes.
The mathematical expression for x is is fewer than 9 is x< 9
Answer:
2
Step-by-step explanation:
Because 2/2 equals 1, and 1 * 2 = 2
Well the answer is -2y-4 but the different terms in this problem are 4 and 5y and 3y where 5y and 3y are like terms
Answer:
f = - 
Step-by-step explanation:
Given f varies directly with m then the equation relating them is
f = km ← k is the constant of variation
To find k use the condition f = - 19 when m = 14
- 19 = 14k ( divide both sides by 14 )
- 
= k
f = - m ← equation of variation
When m = 2 , then
f = - × 2 = -
