UVWX is a parallelogram. What is the measure of angle XUV?
1 answer:
Answer:
We need more info.
Step-by-step explanation:
Even though we need more information to solve this, I can explain how to. if you want me to solve it for you, comment on here and tell me if they gave you <em>any</em> angle measurements. Until then, I'll tell you how.
Look at the attached photo as you read to help you visualize this. Assuming your parallelogram looks roughly like the drawing, you can see that ∠U = ∠W, and ∠X = ∠V. We can determine that because - when working with parallelograms - the angle opposite of the other is always equal. For instance, if the drawing I made is accurate to the one you're looking at, then if ∠U was equal to let's say 120°, then that means that the exact opposite angle, ∠W, would <em>also</em> be equal to 120°.
Offer is still on the table though. If the question gave you any information about <em>any</em> of the degree measures, comment it and I'll solve the problem for you.
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*Correct Question:
Based on the similar triangles shown below, Theodore claims that ∆TUV is transformed to ∆WXY with a scale factor of 3/2. Is Theodore correct?
A. Yes, the triangles are similar with a scale factor of 3/2.
B. No, the triangles are similar with a scale factor of 2/1.
C. No, the triangles are similar with a scale factor of 2/3.
D. No, the triangles are similar with a scale factor of 4/3.
Answer:
C. No, the triangles are similar with a scale factor of 2/3.
Step-by-step explanation:
∆TUV is the original triangle. After transformation, the size reduced to give us ∆WXY. This means ∆TUV was reduced by a scale factor to give ∆WXY. The scale factor should be a fraction, suggesting, the original size of the ∆ was reduced upon transformation.
Thus, the ratio of their corresponding sides = the scale factor.
This is:
If you multiply the side length of ∆TUV by ⅔, you'd get side length of ∆WXY.
So, Theodore is wrong.