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kap26 [50]
3 years ago
9

A technician is checking the operation of the electronic throttle control (ETC) system using a factory or factory-level scan too

l. To perform this test on a Chrysler vehicle, you would use the "throttle follower test" as shown on the scan tool. Which of the following is needed to perform this process? A. An assistant to check that the throttle plate is moving B. Nothing—the throttle will perform a self-test by closing and then opening. C. A running engine D. An assistant to hold open the throttle plate
Computers and Technology
2 answers:
lapo4ka [179]3 years ago
6 0

Answer:

B. Nothing—the throttle will perform a self-test by closing and then opening.

Explanation:

The Electronic throttle test for checking the operation of the ETC or the electronic throttle control which is a workshop or workshop level scan device, you positively need nonentity as it is achieved robotic-ally. And I will encourage you to study ETC deeply. You will have a great time. It is an automobile technology.

alexira [117]3 years ago
4 0

Answer: <em>B . Nothing - the throttle will perform a self - test by closing and the.n </em>

<em>Explanation:The Electronic throttle test for checking the operation of the ETC or the electronic throttle control which is a workshop or workshop level scan device, you positively need nonentity as it is achieved robotic-ally. And I will encourage you to study ETC deeply. You will have a great time. It is an automobile technology. A Technician Is Checking The Operation Of The Electronic Throttle Control To Perform This Test On A Chrysler Vehicle, You Would Use The "throttle Follower Test" As Shown On The Scan Tool. ... A technician is checking the operation of the electronic throttle control (ETC) system using a factory or factory-level scan tool.</em>

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The 7-bit ASCII code for the character ‘&amp;’ is: 0100110 An odd parity check bit is now added to this code so 8 bits are trans
Alex787 [66]

Answer

First part:

The transmitted 8-bit sequence for ASCII character '&' with odd parity will be 00100110. Here leftmost bit is odd parity bit.

Second part:

The invalid bit sequence are option a. 01001000 and d. 11100111

Explanation:

Explanation for first part:

In odd parity, check bit of either 0 or 1 is added to the binary number as leftmost bit for making the number of 1s in binary number odd.

If there are even number of 1s present in the original number then 1 is added as leftmost bit to make total number of 1s odd.

If there are odd number of 1s present in the original number then 0 is added as leftmost bit to keep the total number of 1s odd.  

Explanation for second part:

A valid odd parity bit sequence will always have odd number of 1s.

Since in option a and d,  total number of 1s are 2 and 6 i.e. even number. Therefore they are invalid odd parity check bit sequences.

And since in option b and c, total number of 1s are 5 and 7 i.e. odd numbers respectively. Therefore they are valid odd parity check bit sequences.

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RideAnS [48]

Answer:

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A proxy server, for example, can hide the true origin of a request, thus, keeping your IP address private, and non-visible to the internet. However, this won't necessarily keep malicious attackers from reaching your network. A proxy simply acts as an intermediary between you, and the server you are trying to reach.

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