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lbvjy [14]
4 years ago
7

Please Help!! I always get stuck on these and I am super confused.

Mathematics
1 answer:
kifflom [539]4 years ago
7 0
I believe it would C.
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The hypotenuse of a right triangle is 37 units long. Find the other two sides if the perimeter of the triangle is 84 units. Sepa
taurus [48]

Answer:

The lengths of the legs are 12 and 35 units

Step-by-step explanation:

Let c represent the hypotenuse and a and b represent the legs.  Then the Pythagorean Theorem requires that a^2 + b^2 = c^2 = 37^2 = Hypotenuse^2

Also:  a + b + c = Perimeter = 84 units.  

Since c = 37 units, a + b + 37 units = 84 units, or a + b = 47 units, or a = 47 - b.

Then a^2 + b^2 = 37^2 becomes (47 - b)^2 + b^2 = 37^2, or 1369.  Therefore:

2209 - 94b + b^2 + b^2 = 1369.

Simplifying by combining like terms, we get:  

840 - 94b + 2b^2 = 0, which is a quadratic equation in standard form.

Reducing all terms by division by 2, we get:

420 - 47b + b^2 = 0.  Here the coefficients are a = 1, b = -47 and c = 420.

The discriminant is therefore b^2 - 4ac, or 529, whose square root is ± 23.

Then the b values of this quadratic in b are

      47 ± 23

b = -------------- , so that b is either 35 or 12

             2

and then side a has length a = 47 - b = 12  or  35.

Thus, a = 12 and b = 35, and c is given:  37.

Check:  Is 12^2 + 35^2 = 37^2 true?  Is 144 + 1225 = 1369?  YES

The lengths of the legs are 12 and 35 units.

7 0
3 years ago
Omgggg helppp I need this now plss
Maurinko [17]

Answer:

-4,-4

Step-by-step explanation:

5 0
3 years ago
Find the median<br> 23 ,15, 38 ,34 ,22, 2, 21 ,27 ,26 ,14, 32, 30, 19
xxTIMURxx [149]
First put them in ascending numerical order 
2, 14, 15, 19, 22, 21, 26, 27, 23, 30, 32, 34, 38
Then start to eliminate numbers by pair (the farthest number from each side) until you get to 1 or two numbers left (in the very middle)
in this case you will be left with 26, which means that the median is 26
3 0
3 years ago
Read 2 more answers
i promise i will mark brainliest if the point (-3,4) is the vertex point of the curve of aquadratic function f and -5 is aroot o
Jet001 [13]

Ans:

(x+5)(x+1)+8

Step by step explanation:

-5 was mentioned as the 0 of the first root: (x+5). Then with some maneuvering we can plot (-3,4) then add (x+1) because they land on the same y axis. then we add 8 to get it right on the vertex.

6 0
3 years ago
Write the equation of the line that contains the given point and has the given slope.
mixer [17]
Y=mx+b   m- slope b- y-intercept(where the line crosses the y axis)
31=.5(15)+b plug in your values
31=7.5+b simplify
23.5=b    subtract 7.5 from both sides and your given b
y=.5x+23.5 plug everything into slope intercept form (y=mx+b)
6 0
3 years ago
Read 2 more answers
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