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3 years ago

Find the value of x. 36 21 42 18

Mathematics

2 answers:

Olin [163]3 years ago

8 0

The answer is 42

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Degger [83]3 years ago

5 0

The answer for this is 42. just subtract 152 from 68 and then divide that by 2.

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Rewrite the equation in Ax+By=C form

Ksju [112]

Ax + By = C form of the given equation is –6x + y = –28.

Solution:

Given equation is y – 2 = 6(x – 5).

To write the equation in Ax + By = C format:

y – 2 = 6(x – 5)

y – 2 = 6x – 30

Add 2 on both sides of the equation.

y – 2 + 2 = 6x – 30 + 2

y = 6x – 28

Subtract 6x from both sides of the equation.

y – 6x = 6x – 28 – 6x

y – 6x = –28

Arrange the terms in the equation.

–6x + y = –28

This is in the form of Ax + By = C.

Here A = –6, B = 1 and C = –28.

3 0

3 years ago

A) If the 5th term of an A.P. is double the 7th term, show that the sum of the 17 terms zero.

gayaneshka [121]

Answer:

see explanation

Step-by-step explanation:

The nth term of an AP is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₅ is double a₇ , then

a₁ + 4d = 2(a₁ + 6d) , that is

a₁ + 4d = 2a₁ + 12d ( subtract a₁ from both sides )

4d = a₁ + 12d ( subtract 12d from both sides )

- 8d = a₁

The sum of n terms of an AP is

$S_{n}$ = $\frac{n}{2}$ [ 2a₁ + (n - 1)d ] , substitute values

$S_{17}$ = $\frac{17}{2}$ ( 2(- 8d) + 16d)

= 8.5(- 16d + 16d)

= 8.5 × 0

= 0

5 0

2 years ago

Rewrite by completing the square 2x^2+7x+6=0

Kitty [74]

Answer:

$2x^2+7x+6=0\\\\2(x^2+\frac72x+3)=0\\\\2[x^2+2\cdot x\cdot\frac74+(\frac74)^2-(\frac74)^2+3]=0\\\\2[x^2+2\cdot x\cdot\frac74+(\frac74)^2]-2(\frac74)^2+6=0 \\\\2(x+\frac74)^2-2\cdot\frac{49}{16}+6=0\\\\2(x+\frac74)^2-\frac{49}8+\frac{48}8=0\\\\2(x+\frac74)^2-\frac18=0$