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fiasKO [112]
4 years ago
7

What are the solutions to the equation?

Mathematics
1 answer:
hoa [83]4 years ago
4 0
5w^2 + 10w = 40
5w^2 + 10w - 40 = 0
Divide by 5 through ...
w^2 + 2w - 8 = 0
(w+4)(w-2) = 0
w = -4 or w = 2
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Solve for r in the scientific formula d = rt.<br><br> r = _______
marta [7]
R = d/t is the answer. Hope this helped
4 0
3 years ago
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Is 10−−√ greater than, less than, or equal to 5? Use the drop-down menus to explain your answer. Because 10 lies between two con
Ierofanga [76]

Answer:

\sqrt{10} < 5

Step-by-step explanation:

Given

\sqrt{10} ___ 5

Required

Fill in the gap

First, we need to solve \sqrt{10}

\sqrt{10}= 3.162

So:

\sqrt{10} ___ 5

becomes

3.162 ___ 5

3.162 lies between 3 and 4

So, we can say that

\sqrt{10} lies between 3 and 4

Since:

3.162 is less than 5, the gap can be filled with <.

So, we have: 3.162 < 5

3 0
3 years ago
5. Solve for x:<br> 1/x-1/3=-1/3x
leva [86]

Answer:

(x-3)/9

Step-by-step explanation:

STEP

1

:

           -x

Simplify   ——

           3

Equation at the end of step

1

:

 (3 - x)   -x

 ——————— • ——

   3x      3

STEP

2

:

           3 - x

Simplify   —————

            3x  

Equation at the end of step

2

:

 (3 - x)   -x

 ——————— • ——

   3x      3

STEP

3

:

Canceling Out :

3.1    Canceling out x as it appears on both sides of the fraction line

Final result :

 x - 3

 —————

   9  

hope this helps!!

4 0
3 years ago
Under a dilation, the point (–3, –4) is moved to (–15, –20). What is the scale factor of the dilation?
katrin [286]
The scale factor of the dilation is 5
7 0
3 years ago
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A population of protozoa develops with a constant relative growth rate of 0.6137 per member per day. On day zero the population
Wewaii [24]

Answer:

The population size after seven days will be 171.

Step-by-step explanation:

The population of protozoa can be modeled by the following equation.

Q(t) = Q(0)(1+r)^{t}

In which Q(t) is the population after t days, Q(0) is the initial population and r is the growth rate.

In this problem, we have that:

Q(0) = 6, r = 0.6137

So

Q(t) = 6(1.6137)^{t}

Find the population size after seven days.

This is Q(7).

Q(7) = 6(1.6137)^{7} = 171

The population size after seven days will be 171.

7 0
3 years ago
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