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WARRIOR [948]
3 years ago
5

Write 9*6 as a power with a base 3

Mathematics
1 answer:
ad-work [718]3 years ago
3 0
9=3^2\\6=3\cdot2\\\\9\cdot6=3^2\cdot3\cdot2=2\cdot3^{2+1}=2\cdot3^3\\\\Used:a^n\cdot a^m=a^{n+m}
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Which ratio is equvalent to 7:3
Gala2k [10]

Answer:

21:18

Step-by-step explanation:

3 0
3 years ago
P + 12 &gt; 9<br> A. p &gt; 21<br> B. p &gt; 3<br> C. p &gt; –21<br> D. p &gt; –3
boyakko [2]

Answer:

D. p>-3

Step-by-step explanation:

step1

move 12 to the other side

p>9-12

when you move it changes it's sign from positive to negative

p>-3

3 0
3 years ago
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts
Damm [24]

Answer:

t=2.08 seconds.

Step-by-step explanation:

Well, in this example, H(t)=-0.6cos(2pi/2.5)t+1.5 should be equal to 1.2. If calculated, -0.6cos(0.8pi)t=1.2-1.5 which is equal to -0.6cos(0.8pi)t=-0.3, then cos(0.8pi)t=0.5. The value of cosine in terms of radians when it is equal to 0.5 is pi/3. So, cos(0.8pi)t=cos(pi/3). If simplified, (0.8pi)*t=5pi/3. pi's are cancelled out and t is calculated as 2.08333... If rounded to the nearest hundredth it is 2.08.

4 0
2 years ago
The cost of a fridge has increased by 15% to £828 <br> Work out the original price
Afina-wow [57]
Muliply .15 to 828 and get your answer the add it to 828

4 0
3 years ago
Read 2 more answers
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

3 0
2 years ago
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