3 = q/11....multiply both sides by 11, this cancels out the 11's on the right
11 * 3 = q
33 = q
Answer:
k=73
Step-by-step explanation:
Answer:
30m
Step-by-step explanation:
<em>Since we are not told what to look for, we can find the maximum height reached by the rocket</em>
Given the rocket's flight approximately modeled by the equation
h(t) = - 12t ^ 2 + 36t + 3
At maximum height dh/dt = 0
dh/dt = --24t + 36
0 = -24t + 36
24t = 36
t= 36/24
t = 1.5s
Get the max height
h(1.5) = - 12 (1.5)^ 2 + 36(1.5) + 3
h(1.5) = - 12(2.25) + 54 + 3
h(1.5) = -27 + 57
h(1.5) = 30m
Hence the maximum height reached by the rocket is 30m
Answer: (-2,2)
Explanation: I plugged it into a graphing calc!
Answer: 141.7 ct
Step-by-step explanation: It's quite easy to notate this. Just move the decimal point two units to the right, and there's your notation!
