1 question!

1 answer:

8 0

This is a parabola which opens upwards

y - (-3) = sqrt ((y+1)^2 + (x + 5)^2

(y + 3)^2 = y^2 + 2y + 1 + (x + 5)^2
y^2 + 6y + 9 = y^2 + 2y + 1 + (x + 5)^2

(x + 5)^2 = 4y + 8

(x + 5)^2 = 4(y + 2)

Its C

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263/4 options 65r2 64r7 65 65r3

Reika [66]

Answer:

65R3

Step-by-step explanation:

260/4 is a whole number, so then there would be a remainder 3. The only one with a r3 is D.

Hope this helps :D

4 0

2 years ago

How can i learn times faster like 3's til 12's in Times i have a hard time in my times can someone tell me how i can learn them

iogann1982 [59]

To get better at 12's:
Write down on your paper your 1's facts in column skip 5 and 11 going to 14 (a vertical line - line that goes up and down). To the right of that column, write your two's facts 0 to 8 and repeat again. Then you will have your 12's! Should look as follows

12's:

0 0 = 12 x0
1 2 = 12 x1
2 4 = 12 x2
3 6 = 12 x3
4 8 = 12 x4
6 0 = 12 x5
7 2 = 12 x6
8 4 = 12 x7
9 6 = 12 x8
10 8 = 12 x9
12 0 = 12 x10
13 2 = 12 x 11
14 4 = 12 x 12

5 0

3 years ago

Hey can you please help me posted picture of question

jenyasd209 [6]

The equation of parabola is $x=ay^2$ . If a is positive and $y^2$ is always greater than zero or equal to zero, then x is also greater or equal to zero. This means that parabola is determined for non-negative x and for all real y.

Tha canonical equation of parabola is $y^2=2px$ , where p>0. The branches of this parabola go up in positive y-direction. When you change x to y and y to x, then the branches of parabola go in positive x-direction, that is right.