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3 years ago

Which of the following are factors of 12? 1 And 12 2 And 6 3 And 4

Mathematics

2 answers:

Vikki [24]3 years ago

7 0

Answer:

All three are correct.

Step-by-step explanation:

1x12 is 12, so #1 is correct.

2x6 is 12, so #2 is correct.

3x4 is 12, so #3 is correct.

Phoenix [80]3 years ago

6 0

Answer:

id just learned this a month ago so i think its 2 and 6 i hope u get 100!

Step-by-step explanation:

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QUADRATIC FORMULA SIMPLIFIED PLZ HELP

olga2289 [7]

Answer:

3x² + 5x + 1 = 0 simplified

x = (-5 ± $\sqrt{13}$ )/6 roots

Step-by-step explanation:

Given quadratic formula

3x² + 5x - 5 = - 6

Standard form

ax² + bx + c = 0

Simplifying

3x² + 5x - 5 + 6 = 0
3x² + 5x + 1 = 0

Solving

x = (-5 ± $\sqrt{5^2 -4*3*1}$ )/(2*3)
x = (-5 ± $\sqrt{13}$ )/6

6 0

3 years ago

Tessa claims that a rotation of 90° clockwise about the center of some polygons will carry the polygon onto itself. Select two p

DochEvi [55]

It's square and rhombus

5 0

3 years ago

Read 2 more answers

On a piece of paper, use a protractor to construct right triangle ABC with AB=3 in. , m∠A=90° , and m∠B=45° .

kirza4 [7]

Answer:

1. A. AC=3IN

2. D AND C

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Amanda and her group of friends spent a total of $35.50 on 7 hot dogs and 6 cheese burgers. Greg and his group of friends spent

Alexeev081 [22]

7h + 6b = 35.50
5h + 6b = 30.50

The difference between the 2 totals spent is $5, and there were the same number of burgers, but 2 fewer hotdogs. So $5/2 = $2.50, the cost of a hot dog. Substitute that into the equations to solve for burgers (b)

5(2.50) + 6b = 30.50
12.50 + 6b = 30.50
6b = 18
b = 3

Check the work:
7(2.50) + 6(3) =
17.50 + 18 = 35.50

8 0

3 years ago

Persons taking a 30-hour review course to prepare for a standardized exam average a score of 620 on that exam. Persons taking a

Alina [70]

Given:

30-hour review course average a score of 620 on that exam.

70-hour review course average a score of 749.

To find:

The linear equation which fits this data, and use this equation to predict an average score for persons taking a 57-hour review course.

Solution:

Let x be the number of hours of review course and y be the average score on that exam.

30-hour review course average a score of 620 on that exam. So, the linear function passes through the point (30,620).

70-hour review course average a score of 749. So, the linear function passes through the point (70,749).

The linear function passes through the points (30,620) and (70,749). So, the linear equation is:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-620=\dfrac{749-620}{70-30}(x-30)$

$y-620=\dfrac{129}{40}(x-30)$

$y-620=\dfrac{129}{40}(x)-\dfrac{129}{40}(30)$

$y-620=\dfrac{129}{40}(x)-\dfrac{387}{4}$

Adding 620 on both sides, we get

$y=\dfrac{129}{40}x-\dfrac{387}{4}+620$

$y=\dfrac{129}{40}x+\dfrac{2480-387}{4}$

$y=\dfrac{129}{40}x+\dfrac{2093}{4}$

We need to find the y-value for $x=57$ .

$y=\dfrac{129}{40}(57)+\dfrac{2093}{4}$

$y=183.825+523.25$

$y=707.075$

$y\approx 707.1$

Therefore, the required linear equation for the given situation is $y=\dfrac{129}{40}x+\dfrac{2093}{4}$ and the average score for persons taking a 57-hour review course is 707.1.

4 0

3 years ago