Question

Find the distance between the points (7/3,2) and (1/3,-1)

Answer 1

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{\frac{7}{3}}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{\frac{1}{3}}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{\left( \frac{1}{3}-\frac{7}{3} \right)^2+(-1-2)^2}\implies d=\sqrt{\left( -\frac{6}{3} \right)^2+(-3)^2} \\\\\\ d=\sqrt{(-2)^2+(-3)^2}\implies d=\sqrt{4+9}\implies d=\sqrt{13}$