All categories

3 years ago

On a map, 2 cm represents 30 mi. The actual distance between two towns

Mathematics

1 answer:

nydimaria [60]3 years ago

8 0

Answer:

Step-by-step explanation:

step one:

Given that the scale of the map is

2cm to represent 30 miles

That is every 1 cm is 15 miles in reality

step one:

what we are solving for is the distance in cm on the map so,

1cm rep 15miles

xcm rep 75miles

cross multiply

Xcm= 75/15

X= 5 cm

hence on the map 75miles distance between the two towns is seen as 5 cm

You might be interested in

Ishaan is 222 times as old as Christopher. 353535 years ago, Ishaan was 777 times as old as Christopher.

klemol [59]

<h3><u>Question:</u></h3>

Ishaan is 2 times as old as Christopher. 35 years ago, Ishaan was 7 times as old as Christopher. How old is Christoper now?

<h3><u>Answer:</u></h3>

The present age of Christoper is 42 years old

<h3><u>Solution:</u></h3>

Given that Ishaan is 2 times as old as Christoper

Let the present age of Christoper be "x"

Then, Present age of Ishaan = 2 times as old as Christoper

present age of Ishaan = 2x

<em><u>35 years ago, Ishaan was 7 times as old as Christopher</u></em>

Age of Ishaan 35 years ago = Present age of Ishaan - 35

Age of Ishaan 35 years ago = 2x - 35

Similarly,

Age of christoper 35 years ago = Present age of christoper - 35

Age of christoper 35 years ago = x - 35

From given statement, 35 years ago, Ishaan was 7 times as old as Christopher

Age of Ishaan 35 years ago = 7 times the age of Christoper 35 years ago

(2x - 35) = 7(x - 35)

<em><u>Solve the above equation for "x"</u></em>

2x - 35 = 7x - 245

2x - 7x = -245 + 35

-5x = -210

Thus present age of Christoper is 42 years old

5 0

3 years ago

What is the solution for 2t <5

Luba_88 [7]

Divide 2 from both sides
t < 5/2
Hope this helps!

6 0

3 years ago

Read 2 more answers

For the following pair of functions, find (f+g)(x) and (f-g)(x).

ch4aika [34]

Given:

The functions are

$f(x)=4x^2+7x-5$

$g(x)=-9x^2+4x-13$

To find:

The functions $(f+g)(x)$ and $(f-g)(x)$ .

Solution:

We know that,

$(f+g)(x)=f(x)+g(x)$

$(f+g)(x)=4x^2+7x-5-9x^2+4x-13$

$(f+g)(x)=(4x^2-9x^2)+(7x+4x)+(-5-13)$

$(f+g)(x)=-5x^2+11x-18$

And,

$(f-g)(x)=f(x)-g(x)$

$(f-g)(x)=(4x^2+7x-5)-(-9x^2+4x-13)$

$(f+g)(x)=4x^2+7x-5+9x^2-4x+13$

$(f+g)(x)=(4x^2+9x^2)+(7x-4x)+(-5+13)$

$(f-g)(x)=13x^2+3x+8$

Therefore, the required functions are $(f+g)(x)=-5x^2+11x-18$

and $(f-g)(x)=13x^2+3x+8$ .

7 0

3 years ago

You have solved a system of equations by substitution and got one solution. How were you able to determine it was one solution?

sergeinik [125]

Answer: the variable can not be replaced by any other number

Step-by-step explanation:

7 0

2 years ago

If the discriminant of an equation is positive, which of the following is true of the equation?

Bumek [7]

D>0 that means it has two real solutions (unequal).
<span>It can have one solution only if D=0 and complex solutions only if D<0. </span>

<span>D means discriminant

Answer: B it has two real solutions

hope this helps :)</span>

3 0

3 years ago