Lim as x approches 0 of (e^(5x) - 1 - 5x)/x^2 = lim as x approaches 0 of (5e^(5x) - 5)/2x = lim as x approaches 0 of 25e^(5x)/2 = 25/2 = 12.5
This is a division problem:
Each box holds 20 bags.
800 bags / 20 bags per box = # of boxes
40 boxes are needed.
Total area: pi*9^2 = 81pi
Shaded area = Total area / 3, because 120/360 = 1/3
So Shaded area = 81pi/3 = 27pi
So say for example u have -7 - (-5), think of subtracting integers as adding the opposite, so ur adding the opposite of -5, the opposite of -5 is 5, so ur adding -7 and 5= -2
another one: -15 - (-18)
again, adding the opposite. -15 plus positive 18= 3
