Let
width,w
length, l = 1.6w ...eqn 1
area, a = l × w ...eqn 2
subst for l in eqn 2
a = 1.6 w × w = 4000
4000 = 1.6 w^2
w^2 = 2500
w = 50
subst for w in eqn 1
l = 50 x 1.6 = 80
length = 80 yds
width = 50 yds
Answer: The domain has to be x and the range y. But for independent and dependent variable I can't help. So srry. The picture doesn't show the work. Have a nice day :)
-4y = -3x-2
y = 3/4x + 2/4
y = 3/4x + 1/2
Answer:
Step-by-step explanation:
Three I think.
Donald x x
X X Donald
X Donald X
