The volume of a sphere is (4/3) (pi) (radius cubed).
The volume of one sphere divided by the volume of another one is
(4/3) (pi) (radius-A)³ / (4/3) (pi) (radius-B)³
Divide top and bottom by (4/3) (pi) and you have (radius-A)³ / (radius-B)³ and that's exactly the same as ( radius-A / radius-B ) cubed.
I went through all of that to show you that the ratio of the volumes of two spheres is the cube of the ratio of their radii.
Earth radius = 6,371 km Pluto radius = 1,161 km
Ratio of their radii = (6,371 km) / (1,161 km)
Ratio of their volumes = ( 6,371 / 1,161 ) cubed = about <u>165.2</u>
Note: I don't like the language of the question where it asks "How many spheres...". This seems to be asking how many solid cue balls the size of Pluto could be packed into a shell the size of the Earth, and that's not a simple solution. The solution I have here is simply the ratio of volumes ... how many Plutos can fit into a hollow Earth if the Plutos are melted and poured into the shell. That's a different question, and a lot easier than dealing with solid cue balls.
Let w = the width of the rectangular area. Because the length is 15.5 ft, therefore the calculated area should be at least 170.5 ft². That is (15.5 ft)*(w ft) ≥ 170.5 ft² w ≥ 170.5/15.5 w ≥ 11 ft
