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2 years ago

lexi has $13.00 less that renee. together, they have a total of $95.00. how much money does renee have?

Mathematics

1 answer:

ivanzaharov [21]2 years ago

5 0

Answer:

if I am right Renee would have 82.00 because Lexi has 13.00 less than Renee and together their money's adds up to 95.00 so if you take 13.00 from 95.00 you will have 82.00 that in my opinion

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puteri [66]

Cámbiate de clase mano esa profesora esta depravada

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2 years ago

Marcus drew a quadrilateral with only 1 pair of parallel sides. Which quadrilateral did Marcus draw? parallelogram rhombus trape

SpyIntel [72]

Answer:

Trapezoid

Step-by-step explanation:

We have been given that Marcus drew a quadrilateral with only 1 pair of parallel sides. We are asked to determine the quadrilateral that Marcus drew.

We know that a parallelogram has two pair of parallel sides.

We also know that rhombus is a parallelogram whose 4 sides are equal is measure and rectangle is a parallelogram with opposite sides equal.

Since parallelogram, rhombus and rectangle has two pair of parallel sides, therefore, Marcus didn't draw any of these.

We know that trapezoid has only one pair of parallel sides, therefore, Marcus drew a trapezoid.

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3 years ago

The exponential distribution applies to lifetimes of a certain component. Its failure rate is unknown. Find the probability that

wlad13 [49]

Answer:

a) 0.0821

b) 0.0111

c) 0.0041

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \lambda e^{-\lambda x}$

In which $\lambda$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\lambda x}$

Either it lasts more 5 years or less, or it survives more than 5 years. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 5) + P(X > 5) = 1$

In all 3 cases, we want P(X > 5). So

$P(X > 5) = 1 - P(X \leq 5)$

In which

$P(X \leq 5) = 1 - e^{-5\lambda}$

(a) lambda=.5

$P(X \leq 5) = 1 - e^{-5*0.5} = 0.9179$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9179 = 0.0821$

(b) lambda=0.9

$P(X \leq 5) = 1 - e^{-5*0.9} = 0.9889$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9889 = 0.0111$

(c) lambda=1.1

$P(X \leq 5) = 1 - e^{-5*1.1} = 0.9959$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9959 = 0.0041$

7 0

3 years ago

A ballplayer catches a ball 3.4s after throwing it vertically upward. with what speed did he throw it, and what height did it re

Daniel [21]

From the equation of motion, we know,

$s=ut+\frac{1}{2}at^{2}$

Where s= displacement

u= initial velocity

a= gravitational force

t= time

Displacement is 0 since the ball comes back to the same point from where it was thrown.

A = $-9.8m/s^{2}$ since the ball is thrown upwards.

Plug the known values into the equation.

=> $0=u\left ( 3.4 \right )+\frac{1}{2}\left ( -9.81 \right )(3.4^{2})$

Solving for u gives :

u= 16.67 m/ sec ....... equation (1)

At maximum height, final velocity i.e v is 0

Time take to reach the top = $\frac{3.4}{2} = 1.7 sec$

$v^{2}=u^{2}+2as$

=> $0=(16.67)^{2}+2(-9.81)(s)$

Solving for s we get

s= 14.16 m

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3 years ago

Tell me something you have wanted to say but never told anyone.

Stells [14]

I’m not that smart i just get answers off the internet

6 0

2 years ago