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34kurt
3 years ago
8

Factor completely: 6z2 + 18z

Mathematics
1 answer:
9966 [12]3 years ago
3 0

Answer:

6z(z+3)

Step-by-step explanation:

6z square + 18z

take common..

6z(z+3)

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Can someone please find the volume of this shape and show work for how you did it??
castortr0y [4]

Answer:

221.4m^{3}

Step-by-step explanation:

To work out the volume of this shape you will first need to work out the area of the triangle. To work out the area of the triangle you would multiply the base of 12 by the height of 4.1, which gives you 49.2. You would then need to divide 49.2 by 2, which gives you 24.6. This is because the formula for the area of a triangle is the same as that of a square, however a triangle is half of a square with the same length and width. To work out the volume you would multiply the area of the triangle, which is 24.6 by the height of 9, which gives you 221.4m^{3}

1) Multiply 12 by 4.1.

12*4.1=49.2

2) Divide 49.2 by 2.

49.2/2=24.6

3) Multiply 24.6 by 9.

24.6*9=221.4m^{3}

6 0
3 years ago
Which expression and value represents 9 less than the quotient of 18 and 3?
olga55 [171]

Answer:

kinda hard ,

Step-by-step explanation:

6 1
3 years ago
Read 2 more answers
A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f
Andrews [41]

Answer:

A = \frac{P}{r}\left( e^{rt} -1 \right)

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

                                                \frac{dA}{rA+P} = dt

Integration on both sides gives

                                            \int \frac{dA}{rA+P} = \int  dt

where c is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

                               \int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c

Therefore,

                                        \frac{1}{r} \ln |rA+P| = t+c

Multiply both sides by r.

                               \ln |rA+P| = rt+c_1, \quad c_1 := rc

By taking exponents, we obtain

      e^{\ln |rA+P|} = e^{rt+c_1} \implies  |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}

Isolate A.

                 rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}

Since A = 0  when t=0, we obtain an initial condition A(0) = 0.

We can use it to find the numeric value of the constant c.

Substituting 0 for A and t in the equation gives

                         0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P

Therefore, the solution of the given differential equation is

                                   A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)

4 0
3 years ago
Multiple(x-4)(2x+3) using the distributive property
Vladimir79 [104]

Answer:

See Below

Step-by-step explanation:

x(2x) - 4(2x) + x(3) - 4(3)

= 2x² - 8x + 3x -12

= 2x²-5x-12

8 0
3 years ago
a surgical technician has a set of instruments that must be arranged on a surgical tray in order from the smallest to the larges
Pie
Tools for surgery and patching the person up where their wounds are
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