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alexdok [17]
3 years ago
6

The top of a gate post is in the shape of a square pyramid. The height of the pyramid is 5 inches and each side of the base is 7

.4 inches. Find the volume of wood needed to make the top of the gate post. Round to the nearest tenth. Explain/show how you found the answer.
Mathematics
1 answer:
murzikaleks [220]3 years ago
6 0

Answer:

  91.3 in³

Step-by-step explanation:

The volume of a pyramid can be found using the formula ...

  V = (1/3)Bh

where B represents the area of the base, and h represents the height.

Since the base is square, its area will be the square of the side length, so the volume is ...

  V = (1/3)·(7.4 in)²·(5 in) ≈ 91.3 in³

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Answer:

60%

Step-by-step explanation:

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4 years ago
A researcher wants to check the claim that convicted burglars spend less than 18.7 months in jail, on average. She takes a rando
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Answer:

a. No, there is not enough evidence to support the claim using a level of significance of 1%.

b. Null Hypothesis, H_0 : \mu \geq 18.7 months  

c. Alternate Hypothesis<u>,</u> H_A : \mu < 18.7 months

d. P-value of hypothesis test = 0.0199 or 1.99%

e. We conclude that the convicted burglars spend more than or equal to 18.7 months in jail, on average.

Step-by-step explanation:

We are given that a researcher wants to check the claim that convicted burglars spend less than 18.7 months in jail, on average.

She takes a random sample of 67 such cases from court files and finds that the mean is 16.8 months with a standard deviation of 7.3 months.

<em><u>Let </u></em>\mu<em><u> = true mean time convicted burglars spend in jail.</u></em>

SO, <u>Null Hypothesis</u>, H_0 : \mu \geq 18.7 months   {means that the convicted burglars spend more than or equal to 18.7 months in jail, on average}

<u>Alternate Hypothesis,</u> H_A : \mu < 18.7 months   {means that the convicted burglars spend less than 18.7 months in jail, on average}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                        T.S.  = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean time spent in jail = 16.8 months

             s = sample standard deviation = 7.3 months

             n = sample of cases = 67

So, <em><u>test statistics</u></em>  =   \frac{16.8-18.7}{\frac{7.3}{\sqrt{67} } }  ~ t_6_6

                               =  -2.13

Hence, the value of test statistics is -2.13.

<u>Now, P-value of the test statistics is given by;</u>

      P-value = P( t_6_6 < -2.13) = 0.0199 or 1.99%

  • If the P-value of test statistics is more than the level of significance, then we will not reject our null hypothesis as it will not fall in the rejection region.
  • If the P-value of test statistics is less than the level of significance, then we will reject our null hypothesis as it will fall in the rejection region.

<em>Now, here the P-value is 0.0199 or 1.99% which is clearly higher than the level of significance of 1%, so we will not reject our null hypothesis as it will not fall in the rejection region.</em>

Therefore, we conclude that the convicted burglars spend more than or equal to 18.7 months in jail, on average.

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