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densk [106]
3 years ago
6

Help pleaseeee pleaseeee pleaseeee

Mathematics
1 answer:
Murljashka [212]3 years ago
4 0
We have the same workbook lol
The answer is
Drums: 2/4
milks 4/9
(unless your teacher wants it improper.)
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Substation method x-2y=5 ,<br> 3x-5y=8
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6 0
3 years ago
40 POINTS PLEASE HELP!
White raven [17]

Answer:

-1.70588235294

1. X3,    15x - 10y = 80   15x - 7y = 51

-17y = 29

2. 8 = 1/60 + a. 8 - 1/60 = 7.98333333333

  6 = 1/80 + b. 6 - 1/80 =  5.9875

                                         13.9708333333

3. I genuinely dont know sorry.

4. Pencil = $0.05. Pen = $1.05

Step-by-step explanation:

7 0
3 years ago
Describe how to create a solid model of a simple coffee mug using sweep and other constructive solid geometry operations
anzhelika [568]

Answer:

Step-by-step explanation:

We are going the use the revolve constructive geometry operation

Step one:

Knowing fully well that the simple mug has a cylindrical shape, and all preliminary settings are in place, like the units may be in inches or mm.

We first need to draft out the section of the mug, this will look like an "L" shape with thickness set to whatever dimension you may have in mind.

The next in line is to create an axis using a construction line parallel to the L shape.

Then use the revolve tool to create the cylindrical shape by selecting the axis as the reference of rotation and the angle of rotation set to 360 degrees.

5 0
3 years ago
Find the solution r(t)r(t) of the differential equation with the given initial condition: r′(t)=⟨sin4t,sin7t,9t⟩,r(0)=⟨9,8,3⟩
Makovka662 [10]
\mathbf r'(t)=\langle\sin4t,\sin7t,9t\rangle
\implies\mathbf r(t)=\displaystyle\int\mathbf r'(t)\,\mathrm dt
\mathbf r(t)=\displaystyle\left\langle\int\sin4t\,\mathrm dt,\int\sin7t\,\mathrm dt,\int9t\,\mathrm dt\right\rangle
\mathbf r(t)=\left\langle-\dfrac14\cos4t+C_1,-\dfrac17\cos7t+C_2,-\dfrac92t^2+C_3\right\rangle

With \mathbf r(0)=\langle9,8,3\rangle, we have

\langle9,8,3\rangle=\left\langle-\dfrac14+C_1,-\dfrac17+C_2,C_3\right\rangle
\implies C_1=\dfrac{37}4,C_2=\dfrac{57}7,C_3=8
\implies\mathbf r(t)=\left\langle-\dfrac14\cos4t+\dfrac{37}4,-\dfrac17\cos7t+\dfrac{57}7,-\dfrac92t^2+8\right\rangle
6 0
3 years ago
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