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Greeley [361]
2 years ago
13

3x squared + 6x =05x squared -20x=0How do I find the roots of each equation by factoring.

Mathematics
1 answer:
Ganezh [65]2 years ago
6 0
5/4, -3Solve by Factoring 4x² + 7x - 15 = 02, -5Solve by Factoring x² + 3x - 10 = 0(1 ± i√11) / 2Solve using Quadratic Formula x² - x + 3 = 0(7 ± √3) / 2Solve using Quadratic Formula 2x² - 14x + 23 = 00, 2/3Solve by Factoring 6x² - 4x = 025/4<span>Complete the square to find the value of c.
x² - 5x + c</span>16<span>Complete the square to find the value of c.
x² + 8x + c</span>25<span>Complete the square to find the value of c.
x² - 10x + c</span>49/4<span>Complete the square to find the value of c.
x² + 7x + c</span>81/4<span>Complete the square to find the value of c.
x² - 9x + c</span>9<span>Complete the square to find the value of c.
x² + 6x + c</span>121/4<span>Complete the square to find the value of c.
x² - 11x + c</span>81<span>Complete the square to find the value of c.
x² + 18x + c</span>36<span>Complete the square to find the value of c.
x² - 12x + c</span>1<span>Complete the square to find the value of c.
x² + 2x + c</span>¼<span>Complete the square to find the value of c.
x² - x + c</span>100<span>Complete the square to find the value of c.
x² + 20x + c</span>225<span>Complete the square to find the value of c.
x² - 30x + c</span>9/4<span>Complete the square to find the value of c.
x² + 3x + c</span>4<span>Complete the square to find the value of c.
x² - 4x + c</span>121<span>Complete the square to find the value of c.
x² + 22x + c</span>144<span>Complete the square to find the value of c.
x² + 24x + c</span>2500<span>Complete the square to find the value of c.
x² - 100x + c</span>9/64<span>Complete the square to find the value of c.
x² + ¾x + c</span>1/16<span>Complete the square to find the value of c.
x² - ½x + c</span>f(x) = (x + ½)² + ¾Write in vertex form: f(x) = x² + x + 1f(x) = (x - 1)² + 3Write in vertex form: f(x) = 4 + x² - 2x(-5, -28)What are the coordinates of the vertex of f(x) = (x + 5)² - 28?(9, -21)What are the coordinates of the vertex of f(x) = (x - 9)² - 21?f(x) = (x - 8)² - 56Which function in vertex form is equivalent to f(x) = x² + 8 - 16x?f(x) = (x - 3)² + 9Write in vertex form: f(x) = x² - 6x + 18(-3, -13)What are the coordinates of the vertex of the function f(x) = 6x - 4 + x²?f(x) = (x - 3)² - 8Write in vertex form: f(x) = x² - 6x + 1f(x) = (x + 3)² - 6Write in vertex form: f(x) = x² + 6x + 3f(x) = (x + 5)² - 28Write in vertex form: f(x) = x² + 10x - 3f(x) = (x - 9)² - 21Write in vertex form: f(x) = x² - 18x + 600, -4Solve by graphing.0, 4Solve by graphing.±1Solve by graphing.±2Solve by graphing.-3, 1Solve by graphing.no real solutionsSolve by graphing.0Solve by graphing.<span>2</span>
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Directions for questions 4 &amp; 5: We selected a random sample of 100 StatCrunchU students, 67 females and 33 males, and analyz
GaryK [48]

Answer:

The 95% confidence interval for the difference between means is (-2164.21, -299.13).

The lower limit on the confidence interval is -$2164.21.

The upper limit on the confidence interval is -$299.13.

Step-by-step explanation:

The sample data is:

Gender   Mean          Std. dev.     n

Female    2577.75      1916.29     67

Male        3809.42     2379.47     33

We have to calculate a 95% confidence interval for the difference between means, with a T-model.

The sample 1, of size n1=67 has a mean of 2577.75 and a standard deviation of 1916.29.

The sample 2, of size n2=33 has a mean of 3809.42 and a standard deviation of 2379.47.

The difference between sample means is Md=-1231.67.

M_d=M_1-M_2=2577.75-3809.42=-1231.67

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{1916.29^2}{67}+\dfrac{2379.47^2}{33}}\\\\\\s_{M_d}=\sqrt{54808.468+171572.045}=\sqrt{226380.513}=475.795

The t-value for a 95% confidence interval is t=1.96.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=1.96 \cdot 475.795=932.54

Then, the lower and upper bounds of the confidence interval are:

LL=M_d-t \cdot s_{M_d} = -1231.67-932.54=-2164.21\\\\UL=M_d+t \cdot s_{M_d} = -1231.67+932.54=-299.13

The 95% confidence interval for the difference between means is (-2164.21, -299.13).

6 0
3 years ago
Solve for ppp. 16-3p=\dfrac23p+516−3p= 3 2 ​ p+516, minus, 3, p, equals, start fraction, 2, divided by, 3, end fraction, p, plus
Ksivusya [100]

Given:

The given equation is:

16-3p=\dfrac{2}{3}p+5

To find:

The value of p.

Solution:

We have,

16-3p=\dfrac{2}{3}p+5

Multiply both sides by 3.

3(16-3p)=3\left(\dfrac{2}{3}p+5\right)

48-9p=2p+15

Isolating the variable terms, we get

48-15=2p+9p

33=11p

Divide both sides by 11, we get

\dfrac{33}{11}=p

3=p

Therefore, the required solution is p=3.

7 0
2 years ago
Chords AB and CB intersect at E in circle O, as shown in the diagram below. Secant
Jobisdone [24]

Answer:

Step-by-step explanation:

4 0
2 years ago
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