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Olegator [25]
3 years ago
5

Heights of women have a​ bell-shaped distribution with a mean of 159159 cm and a standard deviation of 55 cm. using​ chebyshev's

theorem, what do we know about the percentage of women with heights that are within 33 standard deviations of the​ mean? what are the minimum and maximum heights that are within 33 standard deviations of the​ mean?
Mathematics
1 answer:
GarryVolchara [31]3 years ago
6 0
Uqwvjkklookhhgcxddssc
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What is 70/10 equivalent fraction?
kaheart [24]
The answer is 7 because 70 ÷ 10 = 7.
6 0
3 years ago
I need help plzs ill give you brainiest
BARSIC [14]
The answer is A, if the two values are the same because equivalent means equal to one another, or the same.
Hope this helps!

8 0
3 years ago
Select the two figures that are similar to the 5 by 10 figure that is shown.
Lapatulllka [165]

Answer:

Figure (i) and (iv)

Step-by-step explanation:

Given:

Optional figure is given in attached file.

We need to find two figures that are similar to the 5 by 10 figure.

All the given figure are m\times n form.

Where m represent the number of rows and n represent the number of columns.

Solution:

Observe that in the given figure 5 by 10, the number of rows is 5 and number of columns is 10, that is, the number of columns is double of that the number of rows.

So we need to find two such figures whose number of columns is double of the number of rows.

From the given figures, figure (i) the number of rows is 2 and number of columns is 4, which is double of number of rows. so it is similar to 5 by 10 figure.

Similarly in figure (iv), the number of rows is 4 and number of columns is 8. so the number of columns is double the number of rows, so it is similar to the figure 5 by 10.

Therefore, the two figures that are similar to 5 by 10 figure are given in attached file such as (i) and (iv).

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%2F7%7D%7B7%5Csqrt%7B10%7D%2F2%20%7D" id="TexFormula1" title="\frac{3/7}{7\sqrt{10}
VashaNatasha [74]

Multiply the numerator and denominator by 7×2 = 14 to eliminate the denominators of those fractions:

\dfrac{\dfrac37}{\dfrac{7\sqrt{10}}2}\times\dfrac{14}{14}=\dfrac{3\times2}{7\sqrt{10}\times7}=\dfrac6{49\sqrt{10}}

Rationalize the denominator by multiplying both numerator and denominator by √10:

\dfrac6{49\sqrt{10}}\times\dfrac{\sqrt{10}}{\sqrt{10}}=\dfrac{6\sqrt{10}}{49(\sqrt{10})^2}=\dfrac{6\sqrt{10}}{49\times10}=\dfrac{6\sqrt{10}}{490}

Lastly, cancel the common factor of 2 in both the numerator and denominator (which comes from 6 = 2×3 and 490 = 2×245):

\dfrac{6\sqrt{10}}{490}=\dfrac{3\sqrt{10}}{245}}

8 0
3 years ago
PLZ HELP DONT UNDERSTAND!!!
victus00 [196]
\bf \textit{area of a triangle}=A=\cfrac{1}{2}bh\qquad &#10;\begin{cases}&#10;b=base\\&#10;h=\textit{height or altitude}&#10;\end{cases}\\\\&#10;-----------------------------\\\\&#10;\textit{area of a trapezoid}\\\\&#10;A=\cfrac{h}{2}(a+b)\qquad &#10;\begin{cases}&#10;a=\textit{base, or one of the parallel sides}\\&#10;b=\textit{base, or the other parallel side}\\&#10;h=\textit{height, the distance between both}\\&#10;\qquad \textit{parallel sides}&#10;\end{cases}
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3 years ago
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