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marissa [1.9K]
4 years ago
15

Does anyone know the answer

Mathematics
1 answer:
8090 [49]4 years ago
3 0
Area of triangle=bh½
(11×2)½=11




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Can someone explain step by step to me
skad [1K]
-  2 /15  - (  - 9/10 )
-2/15  + 9/10  multiply fraction #1 by 2 an fraction  #2 by 3 to get 
-4 /30  +27/ 30 = 23/30

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Which problems can be solved by performing this multiplication?
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Answer: the fourth one

Step-by-step explanation:

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Given that slope is rise/run, write the mathematical equation for calculating the slope of a trend line on a graph.
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Two objects were lifted by a machine. One object had a mass of 2 kilograms and was lifted at a speed of 2m/sec. the other had a
OLga [1]
Sadly, after giving all the necessary data, you forgot to ask the question.
Here are some general considerations that jump out when we play with
that data:

<em>For the first object:</em>
The object's weight is (mass) x (gravity) = 2 x 9.8 = 19.6 newtons
The force needed to lift it at a steady speed is 19.6 newtons.
The potential energy it gains every time it rises 1 meter is 19.6 joules.
If it's rising at 2 meters per second, then it's gaining 39.2 joules of
     potential energy per second.
The machine that's lifting it is providing 39.2 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(2)(4) = 4 joules.

<em>For the second object:</em>
The object's weight is (mass) x (gravity) = 4 x 9.8 = 39.2 newtons
The force needed to lift it at a steady speed is 39.2 newtons.
The potential energy it gains every time it rises 1 meter is 39.2 joules.
If it's rising at 3 meters per second, then it's gaining 117.6 joules of
     potential energy per second.
The machine that's lifting it is providing 117.6 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(4)(9) = 18 joules.

If you go back and find out what the question is, there's a good chance that
you might find the answer here, or something that can lead you to it.

4 0
3 years ago
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