Answer:
A.
Step-by-step explanation:
If
AND
y = x + 7, then by the transitive property of equality:

We can solve for the values of x by getting everything on one side of the equals sign and then solving for x:

We can factor out the common x to get:
x(x + 1) = 0
which tells us by the Zero Product Property that either
x = 0 and/or x + 1 = 0 and x = -1
We are expecting 2 solutions for x since this is a second degree polynomial. We will sub both -1 and 0 into y = x + 7 to solve for the corresponding values of y
y = 0 + 7 so
y = 7 and the coordinate is (0, 7)
y = -1 + 7 so
y = 6 and the coordinate is (-1, 6)
Solution
- The number of possible outcomes in the sample space is simply gotten by multiplying out all the events together.
- There are 3 possible days: Tuesday, Wednesday, or Thursday. Thus, there are 3 possible outcomes.
- There are 3 possible times: 3PM, 4PM, or 5PM. Thus, there are 3 possible outcomes again.
- There are also 9 possible classrooms available meaning another 9 possible outcomes.
- Thus, the total possible outcomes in the sample space is
Isolate the variable by dividing each side by factors that don't contain the variable.
h = −8
Answer:
Given the information above, the area of the square is 361 cm²
Step-by-step explanation:
A square is a shape with four equal sides. So, in order to find the area of the square, we must find the length of each individual side. We can do this by dividing the perimeter by 4 because a square has 4 equal sides meaning they have the same lengths.
The perimeter of the square is 76. So, let's divide 76 by 4.
76 ÷ 4 = 19
So, the lengths of each sides in the square is 19cm.
In order to find the area, we must multiply the length and the width together. Since a square has equal sides, then we will multiply 19 by 19 to get the area.
19 × 19 = 361
So, the area of the square is 361 cm²
3 2/5 x 2 1/3 rewrite
12/5 x 7/3 convert into fractions instead of mixed fraction then multiply straight across
84/15 would be your final answer you might need to reduce it though :) hope i helped