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olasank [31]
3 years ago
10

Gia got some books from Library yesterday she got five books today Gia returned three books Gia has six books how many books did

gia have to begin
Mathematics
1 answer:
makvit [3.9K]3 years ago
6 0

Answer: 4


Explanation:


You can write an algebraic expression to represent the sequence with the books in this way:

  • yesterday she got five books: 5
  • today returned three books: - 3
  • how many books did Gia have to begin: n
  • At the end she has six books, which means that you can set an equality:

       n + 5 - 3 = 6

Now you follow these steps to clear the unknown:

  • do the operations in the left side: n + 2 = 6
  • use subtraction property of equality: n = 6 - 2
  • do the operations: n = 4

And that is the number of books whith which Gina started: 4

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Answer:

1. 170.083 in³

2. 126π in³

3. 92.106 m³

4. 2412.74 in³

5. 612π m³ and 1922 m³

Step-by-step explanation:

1.

Cylinder:

V = \pi r^{2}h               *Plug in numbers*

(3.14)(2.5)^{2}(7)         *Square 2.5*

(3.14)(6.25)(7)        *Solve*

≈ 137.375in^{3}

Sphere:

V = \frac{4}{3}\pi r^{3}              *Plug in numbers*

\frac{4}{3} (3.14)(2.5)^{3}         *Cube 2.5*

\frac{\frac{4}{3}(3.14)(15.625)}{2}         *Divide by 2 and Solve*

≈ 32.7083 in^{3}

Add both volumes

137.375 + 32.7083 ≈ 170.083in^{3}

2.

Cylinder:

V = \pi r^{2}h         *Plug in numbers*

\pi (3)^{2}(10)            *Square 3*

\pi (9)(10)             *Multiply*

90\pi

Sphere:

V = \frac{4}{3} π r^{3}            *Plug in numbers*

\frac{4}{3}\pi (3)^{3}                   *Cube 3*

\frac{4}{3} \pi (27)                   *Multiply*

36\pi

Add both Volumes to get total

90\pi + 36\pi = 126in^{3}

3.

Sphere:

V = \frac{4}{3}\pi r^{3}              *Plug in numbers*

\frac{4}{3} (3.14)(3)^{3}            *Cube 3*

\frac{4}{3} (3.14)(27)            *Multiply*

113.04m^{3}

Cone:

V = \frac{\pi r^{2}h}{3}             *Plug in numbers*

\frac{(3.14)(2)^{2}(5)}{3}           *Square 2*

\frac{(3.14)(4)(5)}{3}             *Solve*

20.93m^{3}

Subtract the volumes to get the volume of the blue area

113.04 - 20.93 = 92.106m^{3}

4.

Sphere:

V = \frac{4}{3} \pi r^{3}            *Plug in numbers*

\frac{4}{3}\pi (8)^{3}                 *Cube 8*

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V = \frac{\pi r^{2}h}{3}            *Plug in numbers*

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\frac{\pi (64)(20)}{3}              *Multiply and Divide*

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Add both volumes

1072.33 + 1340.41 = 2412.74in^{3}

5.

Cylinder:

V = \pi r^{2}h            *Plug in numbers*

\pi (6)^{2}(16)              *Square 6*

\pi (36)(16)             *Multiply*

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V = \frac{\pi r^{2}h}{3}            *Plug in numbers*

\frac{\pi (6)^{2}3}{3}                  *Square 6*

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We have to complete the statement:

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Let us consider the function represented in table.

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Comparing it with standard equation of line y=mx+c with slope 'm'.

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