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steposvetlana [31]
3 years ago
12

-9n>-36? Solve and graph

Mathematics
1 answer:
wlad13 [49]3 years ago
6 0
-9n>-36
divide both sides by -9
n<4 

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There are 4 multiples of 5 between 1-20 5.10.15.20 which are 4/20 aka 1/5 so 1/5 of 200 is 20 times Yaga yeet
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Evaluate StartFraction 3 (6 minus 14) over negative 4 EndFraction.<br> -15<br> -6<br> -1<br> 6
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6

Step-by-step explanation:

First you would do 6 minus 14 and end up with -8

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Cory earns d dollars for every hour he works after school. the weekends, his hourly wage is three times the sum of his after sch
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3d+2

Step-by-step explanation:

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2 years ago
True or False:
fredd [130]
The answer is <em>False
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4 0
3 years ago
The population of a certain country in 1996 was 286 million people. In​ addition, the population of the country was growing at a
Fudgin [204]

Answer:

A) In 2004 the population will reach 306 million.

B) In 2033 the population will reach 386 million.

Step-by-step explanation:

Given : The population of a certain country in 1996 was 286 million people. In​ addition, the population of the country was growing at a rate of 0.8​% per year. Assuming that this growth rate​ continues, the model P(t) = 286(1.008 )^{t-1996} represents the population P​ (in millions of​ people) in year t.

To find : According to this​ model, when will the population of the country reach A. 306 million? B. 386 million?

Solution :

The model represent the population is P(t) = 286(1.008 )^{t-1996}

Where, P represents the population in million.

t represents the time.

A) When population P=306 million.

306 = 286(1.008 )^{t-1996}

\frac{306}{286}=(1.008 )^{t-1996}

1.0699=(1.008 )^{t-1996}

Taking log both side,

\log(1.0699)=\log((1.008 )^{t-1996})

\log(1.0699)=(t-1996)\log(1.008)  

\frac{\log(1.0699)}{\log(1.008)}=(t-1996)  

8.479=t-1996  

t=8.479+1996

t=2004.47

t\approx2004

Therefore, In 2004 the population will reach 306 million.

B) When population P=386 million.

386 = 286(1.008 )^{t-1996}

\frac{386}{286}=(1.008 )^{t-1996}

1.3496=(1.008 )^{t-1996}

Taking log both side,

\log(1.3496)=\log((1.008 )^{t-1996})

\log(1.3496)=(t-1996)\log(1.008)  

\frac{\log(1.3496)}{\log(1.008)}=(t-1996)  

37.625=t-1996  

t=37.625+1996

t=2033.625

t\approx2033

Therefore, In 2033 the population will reach 386 million.

6 0
3 years ago
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