x=2 is directix that means it opens left or right so we must use (y-k)²=4p(x-h) where vertex is (h,k) and p is distance from focus to vertex also shortest distance from vertex to directix the shortest distance from focus to directix is 2p if p>0 then the parabola opens right if p<0 then pareabola opens left
so (-2,0) and x=2 the distance is 4 4/2=2 p=2 wait, positive or negative focus is to the left of the directix so p is negative p=-2
vertex is 2 to the right of the focus and 2 to the left of directix vertex is (0,0)
so (y-0)²=4(-2)(x-0) or y²=-8x is da equation not sure what form is standard tho
