Question

A ball is dropped from the ground. T represents the time in seconds. To find the time you can you the equation Y= -16t^2 +44t. How long is the ball in the air

Answer 1

Answer:

2.75 seconds.

Step-by-step explanation:

We have been given that a ball is dropped from the ground. T represents the time in seconds.

To find the time when the ball was in air, we will equate height of ball with 0 and solve for t.  

$-16t^2+44t=0$

Upon dividing both sides by 4, we will get:

$-4t^2+11t=0$

$-t(4t-11)=0$

$-t=0\text{ (or) }(4t-11)=0$

$t=0\text{ (or) }4t-11=0$

$t=0\text{ (or) }4t=11$

$t=0\text{ (or) }t=\frac{11}{4}$

$t=0\text{ (or) }t=2.75$

Since our given function is a downward opening parabola, so ball will be in air between both t-intercepts.

Since the ball touches the ground at 2.75 seconds, therefore, the ball would be in air for approximately 2.75 seconds.