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zzz [600]
3 years ago
9

Which of the following functions is graphed below

Mathematics
1 answer:
swat323 years ago
5 0
The answer is A. Because greater than or equal to > with line under represents a filled in dot. And > by itself represents an empty dot
You might be interested in
Find the nth term of 1,4,3,16,5,36,7
MakcuM [25]

Answer:

64,9

Step-by-step explanation:

From my understanding the pattern would be:

Every other number is the next consecutive odd number,  

( 1, 3, 5, 7 ) are all of the consecutive odds. (So the next odd is 9.  )

That when we get to the part of where we get every other number for the remaining numbers, if you multiply the next even number by itself (square it).  

4, 16, and 36 ( they are all perfect squares.  )

They are the perfect squares of ( 2, 4, and 6) . So it makes sense that ( 8 ) is the next even number and you would square that and get ( 64 )

I hope this makes sense!!

3 0
2 years ago
1. Consider f(x) = 3x - 5
Rzqust [24]

Answer:

3

Step-by-step explanation:

Here we have the function

f(x)=3x-5

We want to find the following ratio:

\frac{f(x+h)-f(x)}{h}

Note that the limit of this for h\rightarrow 0 is equivalent to the derivative of the function.

Here we have:

f(x+h)=3(x+h)-5=3x+3h-5

And

f(x)=3x-5

Therefore we have

f(x+h)-f(x)=3x+3h-5-(3x-5)=3h

And therefore,

\frac{f(x+h)-f(x)}{h}=\frac{3h}{h}=3

4 0
3 years ago
Find the directional derivative of f(x,y,z)=2z2x+y3f(x,y,z)=2z2x+y3 at the point (−1,4,3)(−1,4,3) in the direction of the vector
Feliz [49]

f(x,y,z)=2z^2x+y^3

f has gradient

\nabla f(x,y,z)=2z^2\,\vec\imath+3y^2\,\vec\jmath+4xz\,\vec k

which at the point (-1, 4, 3) has a value of

\nabla f(-1,4,3)=18\,\vec\imath+48\,\vec\jmath-12\,\vec k

I'm not sure what the given direction vector is supposed to be, but my best guess is that it's intended to say \vec u=15\,\vec\imath+25\,\vec\jmath, in which case we have

\|\vec u\|=\sqrt{15^2+25^2}=5\sqrt{34}

Then the derivative of f at (-1, 4, 3) in the direction of \vec u is

D_{\vec u}f(-1,4,3)=\nabla f(-1,4,3)\cdot\dfrac{\vec u}{\|\vec u\|}=\boxed{\dfrac{294}{\sqrt{34}}}

4 0
3 years ago
**ANSWER QUICKLY PLEASE**
Levart [38]

Answer:

is 6.5y + 10

iready

7 0
2 years ago
Read 2 more answers
Quadratic formula<br> x2 + 3x - 5 = 0
FrozenT [24]

Answer:

2x +3x- 5= 0

5x-5=0

5x=0+5

5x=5

x=5÷5

x=1

5 0
3 years ago
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