Question

A tank containing 64 gallons lost 6 1/4 % through leakage. How much remained in the tank?

Answer 1

Answer: 60 gallon remained in the tank.

Step-by-step explanation:

Since, the initial quantity of the liquid in the tank = 64 gallon,

The quantity that is lost = 6 1/4 % of the initial quantity

= 25/4% of 64

= $\frac{25/4\times 64}{100}$

= $\frac{1600/4}{100}$

= $\frac{1600}{400}$

=  4  gallon,

Hence, the remaining quantity of the liquid = Initial quantity - Lost quantity

= 64 - 4 = 60 gallon.

Answer 2

Hey you!

STEP 1: 6 1/4 = 6.25

STEP 2: 64*6.25% = 4 (64*6 1/4 = 4 as well).

STEP 3: 64 - 4 = 60

60 gallons of gas remained in the tank.