A tank containing 64 gallons lost 6 1/4 % through leakage. How much remained in the tank?

Mathematics

2 answers:

taurus [48]3 years ago

6 0

Answer: 60 gallon remained in the tank.

Step-by-step explanation:

Since, the initial quantity of the liquid in the tank = 64 gallon,

The quantity that is lost = 6 1/4 % of the initial quantity

= 25/4% of 64

= $\frac{25/4\times 64}{100}$

= $\frac{1600/4}{100}$

= $\frac{1600}{400}$

= 4 gallon,

Hence, the remaining quantity of the liquid = Initial quantity - Lost quantity

= 64 - 4 = 60 gallon.

NemiM [27]3 years ago

4 0

Hey you!

STEP 1: 6 1/4 = 6.25

STEP 2: 64*6.25% = 4 (64*6 1/4 = 4 as well).

STEP 3: 64 - 4 = 60

60 gallons of gas remained in the tank.

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Dafna11 [192]

Answer:

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