Answer:
-60
Step-by-step explanation:
The objective is to state whether or not the following limit exists
.
First, we simplify the expression in the numerator of the fraction.

Now, we obtain

and the fraction is transformed into

Therefore, the following limit is

You can plug in
in the equation, hence

The two numbers are <u>12 and 51.</u>
<h3>
EXPLANATION</h3>
To solve this, I did 63-15, to get 48.
I then divided this by 4, to get the first number, which is <u>12.</u>
To find the second answer, I multiplied 12 by 3, which is 36, and then added the 15 back on, to get <u>51.</u>
<u>51 + 12 = </u><em><u>63</u></em>
Answer:
Given equation of the line,

If x = 0,

Thus, the line intercepts y-axis at (0,-2)
If y = 0,

Thus, the line intercepts x-axis at (3.5,0)
By joining these two points in the graph,
We will get the graph of the given line ( shown below )
An expression is defined as a set of numbers, variables, and mathematical operations. The second student is correct.
<h3>What is an Expression?</h3>
In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.
Given One student simplified x⁵ + x⁵ to x¹⁰. The second student simplified x⁵+x⁵ to 2x⁵. Since the simplification of (x⁵+x⁵) is equal to 2x⁵. Therefore, the second student is correct.
Learn more about Expression:
brainly.com/question/13947055
#SPJ1
Answer:
B. 40 meters
Step-by-step explanation:
— Estimating
The rectangle enclosing the path has sides of length 9 m and 14 m, so its perimeter is 2(9+14) = 46 m. The distance covered will be shorter than that.
The distance from A to C is longer than the distance from D to C, so we know the distance will be longer than 2·14+9 = 37 m.
Only one answer choice fits in the range 37 < d < 46.
____
— Detailed calculation
The distance from B to C is the hypotenuse of a right triangle with sides 9 and 12. You will recognize that these side lengths are 3 times the side lengths of a 3-4-5 right triangle, so the hypotenuse distance is 3·5 = 15 meters.
The circuit length is ...
AB +BC +CD +DA = 2 + 15 + 14 + 9 = 40 . . . . meters