(x^4)(3x^3-2)(4x^2+5x)
=(3x^7-2x^4)(4x^2+5x)
=12x^9+15x^8-8x^6-10x^5
answer: 12x^9+15x^8-8x^6-10x^5
the answer is 33 because 3+3=6*10-35+2
(x-h)²+(y-k)²=r² is the equation of a circle with radius of r
so if x-h=4 and y-k=3 then
4²+3²=r²
16+9=r²
25=r²
sqrt both sides
5=r
radius is 5 units
Answer:
point a are (-10,-4) and point I are (-3.875,-10.125)
Step-by-step explanation:
