3 years ago

The sum of the 8th element and the 12th element of an arithmetic progression

Mathematics

1 answer:

jeka943 years ago

7 0

Answer:

448

Step-by-step explanation:

aₙ = a₁ + (n-1)d

a₈ = a₁ + (8-1)d = a₁ + 7d

a₁₂ = a₁ + 11d

a₈ + a₁₂ = 246 = 2a₁ + 18d a₁ + 9d = 123

a₁₀ + a₁₄ = a₁ + 9d + a₁ + 13d = 298 a₁ + 11d = 149

2d = 26

d = 13

a₁ = 6

a₃₅ = 6 + (35-1) x 13 = 448

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