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son4ous [18]
3 years ago
11

I need more help =) ;) :p

Mathematics
1 answer:
mr Goodwill [35]3 years ago
7 0
With what bruh i got you what you need
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Explain how to use a graph of the function f(x) to find f(3)​
fenix001 [56]

Answer:

Just find the coordinate at the point where the x-coordinate is 3

Step-by-step explanation:

F(x) is just another term for Y. The variable of X is the value that you input into the f(x), which just stands for a function. Since the value that they asked for was 3, you know that they inputted the value of 3 as x. Just look where the coordinate at the point where the x-coordinate is 3 to find the answer.

8 0
2 years ago
Read 2 more answers
List all number sets that apply to each number
Tresset [83]
What’s the numbers/ list ?
8 0
3 years ago
Which equation represents a circle with a center at ( -4,9) and a diameter of 10 units
castortr0y [4]

Answer:

(x + 4)² + (y - 9)² = 25

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

here (h, k) = (- 4, 9) and r = 10 ÷ 2 = 5, thus

(x - (- 4))² + (y - 9)² = 5², that is

(x + 4)² + (y - 9)² = 25

3 0
3 years ago
Read 2 more answers
520% of 100<br> 20 1/4% of 3<br> 0.15% of 250<br> 200%of 79<br> 0.3% of 80<br> 0.28% of 50
Tema [17]
Since the word, 'of' means to multiply, whenever we see of multply the two numbers.
 Then there are two ways to dothis, sicne to convert a percentage into a decimal, you devide by 100, we can either do this after we multiply or bfore, it doesn't matter so I'm going to do it after.

1. 520x100=52000/100=520
2. 20.25x3=60.75/100=.6075
3. .15x250=37.5/100=.375
4. 200x79=15800/100=158
5..3x80=24/100=.24
6. .28x50=14/100=.14
8 0
3 years ago
Maria finds a local gym that advertises 67 training sessions for $2052. Find the cost of 153 training sessions.
Ann [662]

Answer:

Cost\ of\ 153\ training\ sessions\ =\$4685.9\approx\$4686

Step-by-step explanation:

Cost\ of\ 67\ training\ sessions\ =\$2052\\\\Cost\ of\ 1\ training\ sessions\ =\frac{Total\ cost}{Total\ training\ sessions}\\\\Cost\ of\ 1\ training\ sessions\ =\frac{2052}{67}\\\\Cost\ of\ 153\ training\ sessions\ =153\times cost\ of\ 1\ training\ sessions\ \\\\Cost\ of\ 153\ training\ sessions\ =153\times\frac{2052}{67}=4685.9\\\\Cost\ of\ 153\ training\ sessions\ \$4685.9\approx4686

7 0
3 years ago
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