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sveticcg [70]
2 years ago
6

What component of a computer system holds the operating system when the computer is not running

Computers and Technology
2 answers:
AlekseyPX2 years ago
4 0
The mass storage devices. Usually a hard drive (HDD) or a solid drive (SSD).
kipiarov [429]2 years ago
3 0
The same thing that holds the operating system when the computer is running.

It is usually a Hard Drive (HDD) or a Solid State Drive (SDD). I would recommend storing the operating system on the SSD because it loads faster, but a lot of computer's don't have SSD's which is why they are stored on Hard Drive's.
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Explanation:

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To find resources on the Internet for your courses, you may need to use a search engine. Suppose that you are collecting informa
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(Business: check ISBN-10) An ISBN-10 (International Standard Book Number) consists of 10 digits: d1d2d3d4d5d6d7d8d9d10. The last
Aneli [31]

Answer:

 The solution code is written in Python 3

  1. digits = input("Enter 9 digits: ")
  2. multiplier = 1
  3. total = 0
  4. for x in digits:
  5.    total += int(x) * multiplier  
  6.    multiplier += 1
  7. checksum = total % 11  
  8. if(checksum == 10):
  9.    print(digits + "X")
  10. else:
  11.    print(digits + str(checksum))

Explanation:

Firstly, use input function to get user input for 9 digits (Line 1)

Next we can use a for-loop to estimate the summation (d1 * 1 + d2 * 2 + d3 * 3 + d4 * 4 + d5 * 5+ d6 * 6 + d7 * 7 + d8 * 8 + d9 * 9) ( Line 6-8)

Then only apply % operator to get the remainder of total and get the checksum (Line 10)

Next create if and else statement to print the digits string joined with X if checksum is 10 else join digits string with checksum value (Line 12 -15)

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Two systems are connected by a router. Both systems and the router have transmission rates of 1,000bps. Each link has a propagat
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Answer:

Two systems are connected by a router. Both systems and the router have transmission rates of 1,000bps. Each link has a propagation delay of 10ms. Also, it takes router 2ms in order to process the packet (e.g. decide where to forward it). Suppose the first system wants to send a 10,000 bit packet to the second system. How long will it take before receiver system receives the entire packet.

Transmission time for first Router = 10,000 bits / 1000 bps = 10 seconds

Receiving time for seond route r= 10,000 bits / 1000 bps = 10 seconds

Propagation delay = 10ms = .01 seconds x 2 for two delays = .02 seconds

First router 2ms to process = .002 seconds

Add all the times together and we get 20.022 seconds which is the same as or 20 seconds and 22 ms

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2 years ago
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