All categories

2 years ago

What is the process of copying items from ram to a storage device?

1 answer:

6 0

This process is called saving. Data in a RAM are temporary and are short-term that is why in order to store the data or items you want to keep for longer period it should be saved in another type of storage which is designed to keep data longer.

You might be interested in

You cannot change data directly in the PivotTable. Instead, you must edit the Excel table, and then ____, or update, the PivotTa

Fudgin [204]

Answer:

d. refresh

Explanation:

The Excel software does not allow a user to change values/data directly in the Pivottable. You will get an error message like "Cannot change this part of a PivotTable report" when you try to type data directly. You will have to edit the Excel Table and then refresh to reflect the updated data.

5 0

3 years ago

Read 2 more answers

Create a program that prints out a list of all the divisors of a number stored in a variable. (If you don’t know what a divisor

UkoKoshka [18]

Answer:

// Program is written in C++ Programming Language

// Comments are used for explanatory purpose

// Program starts here

#include<iostream>

using namespace std;

int main()

{

// Declare integer variable n which serves as the quotient.

int n;

// Prompt to enter any number

cout<<"Enter any integer number: ";

cin>>n;

// Check for divisors using the iteration below

for(int I = 1; I<= n; I++)

{

// Check if current digit is a valid divisor

if(n%I == 0)

{

// Print all divisors

cout<<I<<" ";

}

return 0;

}

7 0

3 years ago

What is the name of the computer through which e-mail messages are sent and received?

nalin [4]

A mail server. --------------------------------------------

8 0

3 years ago

A dns query failure is referred to a higher level domain name server under what condition

zalisa [80]

Within the Flags detail is a flag titled recursion desired. This flag shows whether or not the local DNS should continue to query other DNSs if it is not able to resolve the current query. As DNS is local, it may or may not have the enough information to allow the address to be resolved. If the recursion flag is set, the local <span>DNS will continue to query higher level DNSs until it is able to resolve the address. In short, t</span>he condition is when a flag is raised and it doesn’t have enough <span>information to allow the request.</span>

5 0

2 years ago

Read 2 more answers

Computer Networks - Queues

lyudmila [28]

Answer:

the average arrival rate \lambda in units of packets/second is 15.24 kbps

the average number of packets w waiting to be serviced in the buffer is 762 bits

Explanation:

Given that:

A single channel with a capacity of 64 kbps.

Average packet waiting time $T_w$ in the buffer = 0.05 second

Average number of packets in residence = 1 packet

Average packet length r = 1000 bits

What are the average arrival rate \lambda in units of packets/second and the average number of packets w waiting to be serviced in the buffer?

The Conservation of Time and Messages ;

E(R) = E(W) + ρ

r = w + ρ

Using Little law ;

r = λ × T_r

w = λ × T_w

r / λ = w / λ + ρ / λ

T_r =T_w + 1 / μ

T_r = T_w +T_s

where ;

ρ = utilisation fraction of time facility

r = mean number of item in the system waiting to be served

w = mean number of packet waiting to be served

λ = mean number of arrival per second

T_r =mean time an item spent in the system

T_w = mean waiting time

μ = traffic intensity

T_s = mean service time for each arrival

the average arrival rate \lambda in units of packets/second; we have the following.

First let's determine the serving time T_s

the serving time T_s $= \dfrac{1000}{64*1000}$

= 0.015625

now; the mean time an item spent in the system T_r = T_w +T_s

where;

T_w = 0.05 (i.e the average packet waiting time)

T_s = 0.015625

T_r = 0.05 + 0.015625

T_r = 0.065625

However; the mean number of arrival per second λ is;

r = λ × T_r

λ = r / T_r

λ = 1000 / 0.065625

λ = 15238.09524 bps

λ ≅ 15.24 kbps

Thus; the average arrival rate \lambda in units of packets/second is 15.24 kbps

b) Determine the average number of packets w waiting to be serviced in the buffer.

mean number of packets w waiting to be served is calculated using the formula

w = λ × T_w

where;

T_w = 0.05

w = 15238.09524 × 0.05

w = 761.904762

w ≅ 762 bits

Thus; the average number of packets w waiting to be serviced in the buffer is 762 bits

4 0

3 years ago