What is the process of copying items from ram to a storage device?

1 answer:

6 0

This process is called saving. Data in a RAM are temporary and are short-term that is why in order to store the data or items you want to keep for longer period it should be saved in another type of storage which is designed to keep data longer.

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dangina [55]

Answer:

B. operating tractors and machinery

D. maintaining vehicles and equipment

E. operating irrigation (watering) equipment

F. harvesting fruits and vegetables by hand

Explanation:

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3 years ago

Why did hockey champion Haley wickenheiser feel angry after the Bach said the IOC would make a decision in the next month?

aliina [53]

Haley wickenheiser felt angry after the Bach said the IOC would make a decision in the next month as the IOC says the games will be held no later than summer 2021 but they will still be called the 2020 Tokyo Olympics.

Explanation:

The Tokyo Olympics were postponed until 2021 on Tuesday, ending weeks of speculation that the games could not go ahead as scheduled because of the coronavirus pandemic.
The International Olympic Committee made the decision after speaking with Japanese Prime Minister Shinzo Abe and local organizers.
The IOC said the games will be held not later than summer 2021 but they will still be called the 2020 Tokyo Olympics.
“President Bach said he will agree ‘100%,’ and we agreed to hold the Tokyo Olympics and Paralympics in the summer of 2021 at the latest,” Abe said, saying holding the games next year would be “proof of a victory by human beings against the coronavirus infections.”
The decision came only a few hours after local organizers said the torch relay would start as planned on Thursday.

4 0

3 years ago

Given six memory partitions of 100 MB, 170 MB, 40 MB, 205 MB, 300 MB, and 185 MB (in order), how would the first-fit, best-fit,

nlexa [21]

Answer:

We have six memory partitions, let label them:

100MB (F1), 170MB (F2), 40MB (F3), 205MB (F4), 300MB (F5) and 185MB (F6).

We also have six processes, let label them:

200MB (P1), 15MB (P2), 185MB (P3), 75MB (P4), 175MB (P5) and 80MB (P6).

Using First-fit

P1 will be allocated to F4. Therefore, F4 will have a remaining space of 5MB from (205 - 200).
P2 will be allocated to F1. Therefore, F1 will have a remaining space of 85MB from (100 - 15).
P3 will be allocated F5. Therefore, F5 will have a remaining space of 115MB from (300 - 185).
P4 will be allocated to the remaining space of F1. Since F1 has a remaining space of 85MB, if P4 is assigned there, the remaining space of F1 will be 10MB from (85 - 75).
P5 will be allocated to F6. Therefore, F6 will have a remaining space of 10MB from (185 - 175).
P6 will be allocated to F2. Therefore, F2 will have a remaining space of 90MB from (170 - 80).

The remaining free space while using First-fit include: F1 having 10MB, F2 having 90MB, F3 having 40MB as it was not use at all, F4 having 5MB, F5 having 115MB and F6 having 10MB.

Using Best-fit

P1 will be allocated to F4. Therefore, F4 will have a remaining space of 5MB from (205 - 200).
P2 will be allocated to F3. Therefore, F3 will have a remaining space of 25MB from (40 - 15).
P3 will be allocated to F6. Therefore, F6 will have no remaining space as it is entirely occupied by P3.
P4 will be allocated to F1. Therefore, F1 will have a remaining space of of 25MB from (100 - 75).
P5 will be allocated to F5. Therefore, F5 will have a remaining space of 125MB from (300 - 175).
P6 will be allocated to the part of the remaining space of F5. Therefore, F5 will have a remaining space of 45MB from (125 - 80).

The remaining free space while using Best-fit include: F1 having 25MB, F2 having 170MB as it was not use at all, F3 having 25MB, F4 having 5MB, F5 having 45MB and F6 having no space remaining.

Using Worst-fit

P1 will be allocated to F5. Therefore, F5 will have a remaining space of 100MB from (300 - 200).
P2 will be allocated to F4. Therefore, F4 will have a remaining space of 190MB from (205 - 15).
P3 will be allocated to part of F4 remaining space. Therefore, F4 will have a remaining space of 5MB from (190 - 185).
P4 will be allocated to F6. Therefore, the remaining space of F6 will be 110MB from (185 - 75).
P5 will not be allocated to any of the available space because none can contain it.
P6 will be allocated to F2. Therefore, F2 will have a remaining space of 90MB from (170 - 80).

The remaining free space while using Worst-fit include: F1 having 100MB, F2 having 90MB, F3 having 40MB, F4 having 5MB, F5 having 100MB and F6 having 110MB.

Explanation:

First-fit allocate process to the very first available memory that can contain the process.

Best-fit allocate process to the memory that exactly contain the process while trying to minimize creation of smaller partition that might lead to wastage.

Worst-fit allocate process to the largest available memory.

From the answer given; best-fit perform well as all process are allocated to memory and it reduces wastage in the form of smaller partition. Worst-fit is indeed the worst as some process could not be assigned to any memory partition.

8 0

3 years ago

How did hitles rules in nazi germany exemplify totiltarian rule?

ddd [48]

Answer:

hope this helps if not srry