Is 390 a compatible number or no

Mathematics

2 answers:

IrinaK [193]3 years ago

8 0

Answer:

Yes is is because it is close to 400, I think. "Compatible numbers are close in value to the actual numbers that make estimating the answer and computing problems easier."

Step-by-step explanation:

mezya [45]3 years ago

4 0

Answer:

no. I believe this is the answer

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Illusion [34]

Answer:

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Step-by-step explanation:

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3 years ago

A regular hexagon has an apothem of 2 and a side length of 4 /3/3 its area is

Ne4ueva [31]

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3 years ago

Hey how do you get from standard form to vertex form?

vlabodo [156]

Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be $\mathbf{ax^{2}+bx+c=0}$ where x is the variable.

Completing the square method is as follows:

send the constant term to other side of equal $\mathbf{ax^{2}+bx=-c}$
divide the whole equation be coefficient of $\mathbf{x^{2}}$ , this will give $\mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}$
add $\mathbf{(\frac{b}{2a})^{2}}$ to both side of equality $\mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}$
Make one fraction on the right side and compress the expression on the left side $\mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}$
rearrange the terms will give the vertex form of standard quadratic equation $\mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}$