P(r/w) is the probability of picking a red rose at first picking and a white rose at second picking.
P(w/r) is the probability of picking a white rose at first picking and a red rose at second picking.
P(r/w) =

×

=

P(w/r) =

×

=

Notice that the second fraction is out of 18 because the second picking of rose will be out of 18 since the first rose is not replaced.
P(r/w) equals to P(w/r)
Answer:

Step-by-step explanation:
Since interest is compounded semi-annually (half a year or 6 months), in a spawn of 2 years, the interest will have been compounded 4 times. As given in the problem, each time the interest is compounded, the new balance will be 107% or 1.07 times the amount of the old balance.
Therefore, we can set up the following equation to find the new balance after 2 years:

X should be 7 after doing all the calculation.
Answer:
I dont really understand the question but I think its -7.
Answer: -1 < x < 8
x = 3
x ≠ 2
<u>Step-by-step explanation:</u>
Isolate x in the middle. Perform operations to all 3 sides.
-6 < 2x - 4 < 12
<u>+4 </u> <u> +4</u> <u>+4 </u>
-2 < 2x < 16
<u>÷2 </u> <u>÷2 </u> <u> ÷2 </u>
-1 < x < 8
**************************************************************************
Isolate x. Solve each inequality separately. Remember to flip the sign when dividing by a negative.
4x ≤ 12 and -7x ≤ 21
<u>÷4 </u> <u>÷4 </u> <u> ÷-7 </u> <u>÷-7 </u>
x ≤ 3 and x ≥ 3
Since it is an "and" statement, x is the intersection of both inequalities.
When is x ≤ 3 and ≥ 3? <em>when x = 3</em>
****************************************************************************
Isolate x. Solve each inequality separately.
15x > 30 or 18x < -36
<u>÷15 </u> <u> ÷15 </u> <u> ÷18 </u> <u>÷18 </u>
x > 2 or x < 2
Since it is an "or" statement, x is the union of both inequalities.
When we combine the inequalities, x is every value except 2.
x ≠ 2