11/25
88/1000
Divide each by 8
11. Times 8
125 times 8
Answer:
I came up with -12
Step-by-step explanation:
8 workers = 6 days to complete
x workers = 4 days faster to complete
6/4=1.5 days faster
1.5 x 8 = 12 workers needed to complete the wall in fours days
Answer:
Step-by-step explanation:
#22
<h3>Given </h3>
- Equation x² -4x + 1 = k(x - 4) with equal roots
<h3>To find</h3>
<h3>Solution</h3>
<u>The equation in standard form is:</u>
- x² -4x + 1 = k(x - 4)
- x² - 4x - kx + 1 + 4 = 0
- x² - (k + 4)x + 5 = 0
<u>When the quadratic equation has equal roots its discriminant is zero</u>
- D = 0
- b² - 4ac = 0
- (k + 4)² - 4*5 = 0
- (k + 4)² = 20
- k + 4 = ± √20
- k = - 4 ± √20
- or
- k = -4 ± 2√5
Answer:
How many general admission tickets were purchased? __<u>136</u>__
How many upper reserved tickets we purchased? _<u>300</u>_
Step-by-step explanation:
Let the number of general tickets = g.
Let the number of reserved tickets = r.
6.5g + 8r = 3284
g + r = 436
6.5g + 8r = 3284
(+) -8g + -8r = -3488
--------------------------------
-1.5g = -204
g = 136
g + r = 436
136 + r = 436
r = 300
Answer:
How many general admission tickets were purchased? __<u>136</u>__
How many upper reserved tickets we purchased? _<u>300</u>_
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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