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andrey2020 [161]
3 years ago
6

Part of a tiling design is shown. The center is a regular hexagon. A square is on each side of the hexagon, and an equilateral t

riangle joins the squares. Complete the pattern around the hexagon and calculate the total area of the pattern.
A.403.1 in.
B.503.1 in.
C.1,119.6 in.
D.1,379.4 in.
Mathematics
1 answer:
LiRa [457]3 years ago
3 0
Area of the squares (6):
A 1 = 6 · 10² = 600 in²
Area of the equilateral triangles (6):
A 2 = 6 · 10²√3 / 4 = = 6 · 25 · 1.73 = 259.8 in²
Area of the hexagon:
A 3 = 6 · 10²√3/4 = 259.8 in²
Total area:
600 + 259.8 + 259.8 = 1,119.6 in²
Answer: C ) 
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Find the limit of the function by using direct substitution. limit as x approaches one of quantity x squared plus three x minus
ivann1987 [24]

<u>Answer:</u>

Limit = -1

<u>Step-by-step explanation:</u>

We are given the following function:

x^2 + 3x -1

We are to calculate the limit of this function as x approaches zero.

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6 0
3 years ago
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Semenov [28]
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8 0
3 years ago
The anwsers are<br> A.(0,-1)<br> B.(-2,3)<br> C(-4,0)<br> D(0,-4)
shutvik [7]

Answer:   D.   (0, -4)

=========================================================

Explanation:

If you solve for y, you would get y \le -\frac{1}{4}x-2. The less than or equal to sign shows we shade below the solid boundary line.

Of the four answer choices mentioned, only (0,-4) is in the shaded region. So this is the only solution.

If we plugged the coordinates into the inequality, we get a true statement as shown below

x + 4y \le -8\\\\0 + 4(-4) \le -8\\\\-16 \le -8\\\\

This is a true statement because -16 is to the left of -8 on the number line. So -16 is smaller.

In contrast, if we tried something like (x,y) = (0,-1), then we see...

x + 4y \le -8\\\\0 + 4(-1) \le -8\\\\-4 \le -8\\\\

Which is not true because -4 is actually larger than -8. Use a number line to see this. So (0,-1) is not a solution. The same can be said about (-2,3) and (-4,0) also.

7 0
3 years ago
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