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Please please pleaseeee answer

AVprozaik [17]

Answer:C would be the correct answer

Step-by-step explanation:

3 0

3 years ago

Which is the best interpretation of the solution set for the compound inequality?

saw5 [17]

For this case we must find the solution set of the given inequalities:

Inequality 1:

$3 (2x + 1)> 21$

Applying distributive property on the left side of inequality:

$6x + 3> 21$

Subtracting 3 from both sides of the inequality:

$6x> 21-3\\6x> 18$

Dividing by 6 on both sides of the inequality:

$x> \frac {18} {6}\\x> 3$

Thus, the solution is given by all the values of "x" greater than 3.

Inequality 2:

$4x + 3$

Subtracting 3x from both sides of the inequality:

$4x-3x + 3$

Subtracting 3 from both sides of the inequality:

$x$

Thus, the solution is given by all values of x less than 4.

The solution set is given by the union of the two solutions, that is, all real numbers.

Answer:

All real numbers

8 0

4 years ago

What is the answer of the expression 325-[4x(58-19)+(75 divided by 3

inna [77]

325 - [4(58 - 19) + (75 / 3)]

Divide:

325 - [4(58 - 19) + 25]

Distribute 4:

325 - [232 - 76 + 25]

Subtract:

325 - [156 + 25]

Add:

325 - [181]

Subtract:

144

4 0

3 years ago

. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$P(U |D ) = 0.198$

b

$P(O\ n \ B) = 0.188$

c

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

=>

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

=>

So

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

So

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

So

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

5 0

3 years ago

Find the value of each expression 3[ (20 - 4) / 2] 5(9) / (8 / 4)

storchak [24]

3 [ (20-4) / 2 ]= 3 * 16/2= 3 x 8 =24

5,(9)=5 9/9= 54/9=6

6/8/4= 6/2=3

4 0

3 years ago

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