For this case we have that the point-slope equation of a line is given by:

Where:
m: It is the slope of the line
It is a point through which the line passes
In this case we have to:

Substituting in the equation we have:

Answer:

We just need to replace the value of the slope
Answer:
Step-by-step explanation:
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<span>In general, the height of a projectile is given by
</span>

<span>
where </span>

is the height at time

of a projectile shot upward at velocity

from initial height

<span>.
The acceleration of gravity </span>

<span> We give it a negative sign in the equation because it pulls down.
Let's apply it to each group.
Group A launches a tennis ball straight up with an initial velocity of 19 meters per second.
We have MKS units, positive (upward) velocity and an initial height of 0.
</span>

<span>
Group B launches a tennis ball straight up with an initial velocity of 50 feet per second. Not metric, velocity +50, initial height zero.
</span>

<span>
Group C drops a tennis ball from a height of 19 meters.
MKS, initial height 19, initial velocity zero.
</span>

<span>
Group D drops a tennis ball from a height of 50 feet.
</span>

<span>
</span>
Answer: -2
Step-by-step explanation:
9e-7=7e-11
-7e -7e
2e-7=-11
+7 +7
2e=-4
/2 /2
e=-2
The answer is 44 h(-7)= -7^2 -5 =49-5=44