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sdas [7]
3 years ago
14

Lauren would like to find the midpoint of a line segment that has endpoints at (–0.5, 3) and (4, 7.5). Which statements are true

? Check all that apply.
Mathematics
2 answers:
Bond [772]3 years ago
7 0

Answer:

Lauren could solve 7.5 + 3 / 2 to find the y-intercept.

Lauren could solve (1/2)(4+0.5) to find the x-intercept.

Finding the midpoint is equivalent to partitioning a line segment a 1:1 ratio.

Step-by-step explanation:


barxatty [35]3 years ago
5 0

Answer with explanation:

We have to find the mid point of the points P (-0.5,3) and Q(4,7.5) that lie on two dimensional coordinate system .Suppose mid point of PQ is R(x,y).

→Mid point of a line segment  means that point on the line segment which divides the Segment  in the ratio of 1:1.

→Mid point formula , point joining (x_{1},y_{1}),(x_{2},y_{2}) is

         (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

→So, Mid point of  line segment that has endpoints at (–0.5, 3) and (4, 7.5) is

         (\frac{-0.5+4}{2},\frac{3+7.5}{2})=(\frac{3.5}{2},\frac{10.5}{2})=(1.75,5.25).

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HACTEHA [7]

Step-by-step explanation:

porportional means they scale by the same ratio

L / W = L_1 / W_2 = 5.4 / 2.5 = 6.21 / x

solve for x

3 0
2 years ago
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A line passes through the point (–2, 7) and has a slope of –5. A coordinate plane. What is the value of a if the point (a, 2) is
Nana76 [90]

Y = mx + c

7= (-5)(-2)+ c

7= 10 +c

7-10=c

-3=c

Equation of the line: y = -5x-3

Sub in (a, 2)

2= - 5(a)-3

2+3= -5a

5= - 5a

1= - a

A = -1

8 0
2 years ago
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HELP!!! First gets Top Answer!!!
Marta_Voda [28]
It is approximately -.4048

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4 0
3 years ago
An equation parallel and perpendicular to 4x+5y=19
UNO [17]

Answer:

Parallel line:

y=-\frac{4}{5}x+\frac{9}{5}

Perpendicular line:

y=\frac{5}{4}x-\frac{1}{2}

Step-by-step explanation:

we are given equation 4x+5y=19

Firstly, we will solve for y

4x+5y=19

we can change it into y=mx+b form

5y=-4x+19

y=-\frac{4}{5}x+\frac{19}{5}

so,

m=-\frac{4}{5}

Parallel line:

we know that slope of two parallel lines are always same

so,

m'=-\frac{4}{5}

Let's assume parallel line passes through (1,1)

now, we can find equation of line

y-y_1=m'(x-x_1)

we can plug values

y-1=-\frac{4}{5}(x-1)

now, we can solve for y

y=-\frac{4}{5}x+\frac{9}{5}

Perpendicular line:

we know that slope of perpendicular line is -1/m

so, we get slope as

m'=\frac{5}{4}

Let's assume perpendicular line passes through (2,2)

now, we can find equation of line

y-y_1=m'(x-x_1)

we can plug values

y-2=\frac{5}{4}(x-2)

now, we can solve for y

y=\frac{5}{4}x-\frac{1}{2}


4 0
3 years ago
Always, sometimes, or never true
Kitty [74]
I think it’s always because the absolute value is always positive.
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3 years ago
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