Answer: 
Step-by-step explanation:
Given
Survey shows that 16% of college students have dogs and 38% have HBO subscription
Probability that a random person have both is
![\Rightarrow P_o=0.16\times 0.38\quad [\text{As both events are independent}]\\\Rightarrow P_o=0.0608](https://tex.z-dn.net/?f=%5CRightarrow%20P_o%3D0.16%5Ctimes%200.38%5Cquad%20%5B%5Ctext%7BAs%20both%20events%20are%20independent%7D%5D%5C%5C%5CRightarrow%20P_o%3D0.0608)
The probability that the random person has neither of the two is

1049841
1053000x.003=3159
1053000-3159=1049841
Answer:
f(x) = x
Step-by-step explanation:
note : slope is positive 1, so the x term must be positive
also note the graph intersects the curve at y = 0, which means that they y-intercept is zero .
if we substitute this into the general equation for a line
y = mx + b, where m = +1 and b = 0,
we get y = x
or f(x) = x (in function form)
612/6=102
check: 6x102=612
Hope this helped! :))
Complete question:
Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby this mention is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect so the probability of a girl is 0.5. Assume that the group consists of 36 couples.
A) Find the mean and standard deviation for the number of girls in groups of 36 births.
B) Use the range rule of thumb to find the values separating results that are significantly low and significantly high.
C) Is the result of 33 girls significantly high? A result of 33 girls would suggest the method is effective or is not effective?
Answer:
a) mean = 18
Standard deviation =3
b) low range = 12
High range = 24
c) The result of 33 girls is significantly high. Yes, the method is effective.
Step-by-step explanation:
Given:
p = 0.5
n = 36
a) The mean is the product of n and p
Mean u = np
u = 36 * 0.5 = 18
The standard deviation is the square root of the product of n and p&q.
S.d ó = 


b) To find the range rule of thumb:
• For low range
Low range = u - 2ó
= 18 - (2 * 3)
= 12
• High range
= u + 2ó
= 18 + (2*3)
= 24
c) The result is significantly high, because 33 is greater than 24 girls.
A result of 33 girls would prove the method as effective.